Given :
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by
.
To Find :
Find the time at which the concentration is a maximum. b. Find the maximum concentration.
Solution :
For maximum value of x, K'(x) = 0.

Since, time cannot be negative, so ignoring x = -3 .
Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6
Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.
Hence, this is the required solution.
Answer:
degrees
Step-by-step explanation:
Sum of 3 angles in a triangle is 180..
The angles given are:
60
7x + 12
1
So we sum to 180 and write:

Also, straight angle is 180 degrees, thus Angle 1 and (14x + 9) angle is sum to 180, thus we can write:

Or we can write this as:

We substitute this expression for Angle 1 into 1st equation we got and solve for x first,

Since x = 9, the angle "14x + 9" would be:
14(9) + 9 = 135
Hence Angle 1 would be:

Answer:
(check the image below)
Step-by-step explanation:
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