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nalin [4]
2 years ago
12

Can someone help me?

Mathematics
2 answers:
Law Incorporation [45]2 years ago
6 0
The answer to your question is 21
tatyana61 [14]2 years ago
4 0

Answer:

21

Step-by-step explanation:

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At the gym Merl swims every 6 days, runs every 4 days and cycles every 16 days. If she did all 3 activities today in how many da
garri49 [273]

Answer:

48 days

Step-by-step explanation:

Swim = every 6 days

Run = every 4 days

Cycles = every 16 days

Find the lowest common multiple of 6, 4 and 16

6 = 6, 12, 18, 24, 30, 36, 42, and 48

4 = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

16 = 16, 16, 32, 48, 64, 80, 96, 112, 128, 144, 160

The LCM of 6, 4 and 16 is 48

Therefore,

If she did all 3 activities today, she will do all 3 activities again in the next 48 days

8 0
2 years ago
Solve this equation -9-6+12h+40=22<br><br> A. h=24<br> B. h= -4/7<br> D. h= -4
BartSMP [9]
-9-6+12h+40=22
12h+25=22
12h=-23
h=-23/12
8 0
3 years ago
Read 2 more answers
Solve the following: - 3 raised to 1 by 5 the whole raised to 4 (3^1/5)^4
Diano4ka-milaya [45]

Answer:

8.30256

Step-by-step explanation:

Step 1: Write out expression

((-3)^{\frac{1}{5} })^{4(3^{\frac{1}{5} })^4

Step 2: Use BPEMDAS to evaluate

(-1.24573)^{4(3^{\frac{1}{5} })^4

(-1.24573)^{4(1.24573)^4

(-1.24573)^{4(2.40822)

(-1.24573)^{9.6329}

= 8.30256

And we have our answer!

8 0
3 years ago
If four pounds of a certain candy cost $10 how manu pounds of that candy can be purchased for $12
dangina [55]
4.8 pounds, set it up as 4 over ten times x over 12, 4 times 12 divided by ten equals 4.8
8 0
2 years ago
Solve for x. 3(3x - 1) + 2(3 - x) = 0
olga nikolaevna [1]
The equation given in the question is
3(3x - 1) + 2(3 - x) = 0
9x - 3 + 6 - 3x = 0
6x + 3 = 0
6x = - 3
x = - (3/6)
   = - (1/2)
So the value of x as has been determined above is -1/2. I hope the procedure is clear enough for you to understand.<span>You can always use this method for solving problems that are similar in type without requiring any help from outside. </span>



8 0
3 years ago
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