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2 years ago

Find the points on x-axis where the circle with equation X square + Y square - 8 x - 8 Y - 9 = 0

Mathematics

1 answer:

Mamont248 [21]2 years ago

4 0

Answer:

(- 1, 0) and (9, 0 )

Step-by-step explanation:

To find the x- intercepts let y = 0 in the equation and solve for x, that is

x² + y² - 8x - 8y - 9 = 0

x² - 8x - 9 = 0 ← in standard form

(x - 9)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 9 =0 ⇒ x = 9

x + 1 = 0 ⇒ x = - 1

x- intercepts are (- 1, 0 ) and (9, 0 )

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Equation of the circle (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

Step(i):-

Given endpoints of diameter P(−2, 1) and Q(8, 9)

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Centre = $(\frac{-2+8}{2} ,\frac{1+9}{2} )$

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Step(ii):-

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Final answer:-

Equation of the circle

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x² -6x +y² -10y -7= 0

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