All categories

3 years ago

Find the points on x-axis where the circle with equation X square + Y square - 8 x - 8 Y - 9 = 0

Mathematics

1 answer:

Mamont248 [21]3 years ago

4 0

Answer:

(- 1, 0) and (9, 0 )

Step-by-step explanation:

To find the x- intercepts let y = 0 in the equation and solve for x, that is

x² + y² - 8x - 8y - 9 = 0

x² - 8x - 9 = 0 ← in standard form

(x - 9)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 9 =0 ⇒ x = 9

x + 1 = 0 ⇒ x = - 1

x- intercepts are (- 1, 0 ) and (9, 0 )

You might be interested in

Can someone help me with this please???

AysviL [449]

Answer:

diarrhea

Step-by-step explanation:

6 0

3 years ago

Simplify the expression: 6 + 3(x + 4) A 6 + 3x + 12 B 9x + 36 C 3x + 18 D 9x + 4

zepelin [54]

Answer:

Step-by-step explanation:

6 + 3(x + 4)

= 6 + 3x + 12

= 3x + 18

5 0

2 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

3 years ago

Estimate the quotient

juin [17]

57.8 can be rounded to 60 because 57.8 is closer to 60 than 50 and 81 is relatively close to 80. if we had to estimate the quotient, we would have

60 ÷ 80 = 0.75

2.8 can be rounded to 3 because 2.8 is closer to 3 than it is to 2 and 6 can be left alone because it will make our division easier.

3 ÷ 6 = 0.5

#11

737.5 can be rounded to 700 and 9 can be rounded to 10.

700 ÷ 10 = 100

4 0

3 years ago

Rewrite the expression without using grouping symbols 11(23-x)

Triss [41]

7 0

3 years ago