Question

Find the points on x-axis where the circle with equation X square + Y square - 8 x - 8 Y - 9 = 0

Answer 1

Answer:

(- 1, 0) and (9, 0 )

Step-by-step explanation:

To find the x- intercepts let y = 0 in the equation and solve for x, that is

x² + y² - 8x - 8y - 9 = 0

x² - 8x - 9 = 0 ← in standard form

(x - 9)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 9 =0 ⇒ x = 9

x + 1 = 0 ⇒ x = - 1

x- intercepts are (- 1, 0 ) and (9, 0 )