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Karolina [17]
3 years ago
11

What is the area of the parallelogram?

Mathematics
1 answer:
Ulleksa [173]3 years ago
6 0

The area of a parallelogram is denoted by b * h, where b is the base and h is the height.

In this case, the b is 15 inches, and the h is 4 inches. Multiply these together and you get: 15 * 4 = 60 square inches.

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The area of a square garden is 50 m². How long is the diagonal?
yan [13]
D=10 m is the answer.......

3 0
3 years ago
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Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 3 cubic feet
gtnhenbr [62]

Answer:

Therefore the height of the water in the pool changes at the rate of \frac{1}{3\pi} feet per minute.

Step-by-step explanation:

Given that  the shape of swimming pool is right circular cylinder.

The  rate of water pouring in the pool = 3 cubic feet per minute.

It means the rate of change of volume is 3 cubic feet per minute.

\frac{dv}{dt}=3 cubic feet per minute.

When the volume of the swimming pool changed it means the height of the water level of the pool change and the radius of the swimming pool remains constant.

Let the height of the pool be h.

The volume of the pool is = \pi 3^2 h  cubic feet

                                          =9\pi h cubic feet

Therefore,

v =9\pi h

Differentiating with respect to t

\frac{dv}{dt}= 9\pi \frac{dh}{dt}

Putting \frac{dv}{dt}=3

3=9\pi \frac{dh}{dt}

\Rightarrow \frac{dh}{dt} =\frac{3}{9\pi}

\Rightarrow \frac{dh}{dt} =\frac{1}{3\pi}

The change of height of the pool does not depend on the depth of the pool.

Therefore the rate of change of height of the water in the pool is \frac{1}{3\pi} feet per minute.

6 0
3 years ago
I’m not sure how to figure out what numbers to fill in and the equation
Tanzania [10]
Lets calculate linear equation
assume
y = f(x)= mx +b

now given
f(0) = 2
m×0+b = 2
b = 2
so b = 2
given f(4) = 0.125 = 1/8
m×4 + 2 = 1/8
4m = 1/8-2= -15/8
m = -15 /(8×4) = -15/32

so linear equation is
y = mx + b = -15x/32 + 2


exponential equation is same as you have written

y = 2(0.5)^x

now put values of x in each equation to get value of y

x =0

linear y = -15×0/32+2 = 2

exp y = 2(0.5)^0 = 2×1 = 2

x =1

linear y = -15×1/32+2 = 2-15/32= 49/32

exp y = 2(0.5)^1 = 2×1/2 = 1

x =2

linear y = -15×2/32+2 = 2-30/32= 17/16

exp y = 2(0.5)^2 = 2×1/4 = 0.5

x =3

linear y = -15×3/32+2 = 2-45/32= 19/32

exp y = 2(0.5)^3 = 2×1/8= 0.25

x =4

linear y = -15×4/32+2 = 2-60/32= 4/32 = 0.125

exp y = 2(0.5)^4= 2×1/16 = 1/8= 0.125
8 0
3 years ago
In the equation y=-5x, what is the constant of proportionality?
sattari [20]
y = 5x, so 5 is the constant of proportionality
8 0
3 years ago
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What is the area of trapezoid ABCD ? Enter your answer as a decimal or whole number in the box. Do not round at any steps. units
lidiya [134]

Answer:

37.5 sq. units.

Step-by-step explanation:

The coordinate of vertices of trapezoid ABCD are given,

From the diagram it is clear the area of ABCD = \frac{1}{2}\times AB \times (AD + BC) {Since, AD ║ BC and AB is the perpendicular distance between the parallel lines }

Now, AB = \sqrt{(- 3 - 1)^{2}+ (2 - 5)^{2}  } = 5 units

AD = \sqrt{(- 3 - 0)^{2}+ (2 - (-2))^{2}  } = 5 units

Again, BC = \sqrt{(1-7)^{2}+ (5 - (-3))^{2}  } = 10 units

Therefore, the area of trapezoid ABCD = \frac{1}{2} (10 + 5) \times 5 = 37.5 sq. units. (Answer)

We know, that the distance formula between two points (x_{1}, y_{1}) and  (x_{2}, y_{2}) is  

\sqrt{(x_{1} - y_{1} )^{2} + (x_{2} - y_{2} )^{2}  }.

7 0
3 years ago
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