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statuscvo [17]
3 years ago
6

What type of crust is colliding? Japan Trench Eurasian Plate Pacific Plate

Chemistry
1 answer:
Mkey [24]3 years ago
4 0

Answer: The Eurasian Plate or both the Eurasian and Pacific Plate.

Explanation:

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Referring to the scale is a way to estimate the wind speed.
Sonja [21]

<em><u>Answer:</u></em>

The Beaufort scale measures wind speed.

<em><u>Explanation:</u></em>

One way to measure wind speed is by observing its effects on objects. In 1805, a British naval officer named Sir Francis Beaufort developed a wind speed scale that refers to the movement of objects. The Beaufort Scale is a good way to introduce your students to the concept of wind speed.

8 0
3 years ago
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The elements of the earth are in a constant process of being
Alja [10]

Answer:

A: Recycled

Explanation:

5 0
3 years ago
If different masses of water are heated to the same temperature, which sample will absorb more energy? Base your argument on the
MArishka [77]

Answer:

Heat, energy that is transferred from one body to another as the result of a difference in temperature.

Explanation:

5 0
2 years ago
Once the reaction has occurred as completely as possible, what mass (in g) of the excess reactant is left
Vera_Pavlovna [14]
So C12 is the limiting reactant and P4 is the excess
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Hope i helped
6 0
3 years ago
A 72.0-gram piece of metal at 96.0 °C is placed in 130.0 g of water in a calorimeter at 25.5 °C. The final temperature in the ca
tekilochka [14]

Answer: The answer is S = 0.1528 cal/g °C

Explanation:

By the law of conservation of energy, energy is neither created nor destroyed.

So, energy lost by metal pieces is equal to the energy gained by water in the calorimeter.

Specific heat of water is 1 cal/g °C

⇒ heat energy  Q = mSΔT, where m = mass of a substance

                                                        S = specific heat

                                                        ΔT = change in temperature

Now, the heat lost by metal piece, Q = 72×S×(96-31)

                                                      = 4680×S cal

Heat gained by water, Q = 130×1×(31-25.5)

                                        = 715 cal

⇒ 4680×S = 715.

⇒ S = 0.1528 cal/g °C.

6 0
3 years ago
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