) If a 6 ft tall petrified stump casts a 3 ft

A bricklayer can build a wall of a certain size in 5 hours. Another bricklayer can do the same job in 4 hours. If the bricklayer

Tju [1.3M]

Answer:

b

Step-by-step explanation:

7 0

3 years ago

50 POINTS !! PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

maks197457 [2]

Answer:

16

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

a is a leg
b is another leg
c is the hypotenuse

Step-by-step explanation:

Step 1: Define

Identify variables

Leg a = a

Leg b = 12

Hypotenuse c = 20

Step 2: Solve for a

Substitute in variables [Pythagorean Theorem]: a² + 12² = 20²
Evaluate exponents: a² + 144 = 400
[Subtraction Property of Equality] Isolate a term: a² = 256
[Equality Property] Square root both sides: a = 16

3 0

3 years ago

Read 2 more answers

A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat

konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles

First, we need to find b:

$a^{2} + b^{2} = h^{2}$ (1)

$b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles$

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

$\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})$

$2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:

$0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

$\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h$

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0

2 years ago

Each side of a square x units long is decreased by 9 units. which expression represents the area of the new square in square uni

Vinil7 [7]

Answer:

a= (x-9)2

a=x2-18x+81

7 0

3 years ago

For the triangles to be congruent by hl, what must be the value of x? 8 9 17 34

lora16 [44]

Using equations we know that the value of x needs to be (E) 4 to make HL congruent to AC.

<h3>What are equations?</h3>

A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.

The point-slope form, standard form, and slope-intercept form are the three main types of linear equations.

So, HL is a hypotenuse that will be congruent to the hypotenuse AC.

We know that HL is 3x + 3.

Ac is 15.

Then the equation will be:

3x + 3 = 15

Now, solve the equation to get x as follows:

3x + 3 = 15

3x = 15 - 3

3x = 12

x = 12/3

x = 4

Therefore, the value of x needs to be (E) 4 to make HL congruent to AC.

Know more about equations here:

brainly.com/question/28937794

#SPJ4

Correct question:
For the triangles to be congruent by hl, what must be the value of x?

a. 8

b. 9

c. 17

d. 3

e. 4

8 0

1 year ago