This is a division problem. You can use the standard algorithm of 128/ 5. Or you can create equal groups (draw five circles) and count out eggs until you distribute them all. I would start with 20 in each circle. That would be 20+ 20+ 20+ 20+ 20= 100 Then think 128-100= 28 Next count by 5's. 5+ 5+ 5+ 5+ 5= 25 Then think what is 28-25= 3 so 128/ 5= 25 with a reminder of 3 eggs left over.
step 2 would be 10
step 4 would be 10x-x = 9x =7
x = 7/9
Answer:
I believe the answer is A.
THEY ARE ALWAYS PARALLELOGRAMS
22.4
If the bottom side is 20 cm, then each line BE and CE would each be 10 cm.
Now, just focus on the top left triangle. You have one side with 20 cm, and the other side with 10 cm. You are left with the hypotenuse, which you need to figure out the value of.
Since this is a right triangle, you can use the Pythagorean theorem -> a^2 + b^2 = c^2 where c is the hypotenuse.
20^2 + 10^2 = c^2
400 + 100 = c^2
500 = c^2
22.36 = c
