All categories

3 years ago

Four runners are training for long races. Noah ran 5.123 miles, Andre ran 6.34 miles, Jada ran 7.1 miles, and Diego ran 8 miles.

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

5 0

Answer:

<h2>a. 26.563 miles</h2><h2>b. 1.977 miles</h2>

Step-by-step explanation:

Given, 

Distance Noah ran = 5.123 miles

Distance Andre ran = 6.34 miles

Distance Jada ran = 7.1 miles

Distance Diego ran = 8 miles

Hence,

a. Total running distance of four runners

= (5.123 + 6.34 + 7.1 + 8) miles

= 26.563 miles (Ans)

b. Distance more ran by Jada than Noah

= (7.1 - 5.123) miles

= 1.977 miles (Ans)

Ipatiy [6.2K]3 years ago

4 0

Answer:

26.56300 1.97700

Step-by-step explanation:

You add up all of them which was 26.5630 then you do 7.1-5.123+1.97700

You might be interested in

Which of the following equations is the result after the first step in solving 3x + 6 = 12?

tensa zangetsu [6.8K]

3x=18 because you add the like terms 6 and 12

7 0

3 years ago

Can someone please answer this and explain how you got it? Or just show your work for it please and thank u <3

serg [7]

Answer:

please mark me as brainlist please

Step-by-step explanation:

we know, ∠BGA = 90

In right angled triangle BGA

AB = 12 cm (diameter of circle)

⇒ (AB)2 = (AG)2 + (BG)2

⇒ 122 = 82 + (BG)2

⇒ BG = 4√5

In right angled triangle BCG

Let CG be x cm.

⇒ (BC)2 = (CG)2 + (BG)2

⇒ (BC)2 = x2 + (4√5)2 ----(1)

As we know,

⇒ (BC)2 = CG × CA ----(2)

From equation (1) and equation (2)

⇒ x2 + (4√5)2 = x × (x + 8)

⇒ x2 + (4√5)2 = x2 + 8x

⇒ 8x = 80

⇒ x = 10 cm

From equation (2)

⇒ (BC)2 = CG × CA

⇒ (BC)2 = 10 × 18 = 180

⇒ BC = √180 = 6√5

6 × 5 = 30

5 0

3 years ago

Exercise 30 please , show work

ArbitrLikvidat [17]

$-8(2a-3b)-5(6b-4a)=\\=-8 \times 2a -8 \times (-3b)-5 \times 6b-5 \times (-4a)= \\
=-16a+24b-30b+20a= \\
=20a-16a+24b-30b= \\
=(20-16)a+(24-30)b= \\
=4a-6b$

3 0

3 years ago

Read 2 more answers

Frank has a 2-digit number on his baseball uniform. the number is a multiple of 10 and has 3 for one its factors. what three num

Feliz [49]

A. What three numbers could possibly be on his uniform.
B. Probability of being a multiple of 10 and is two digits and has a 3 as a factor.
C. Frank has a 30 on his uniform. The number is a multiple of 10 and one factor of the number is 3.

4 0

3 years ago

What is 5 divided by 3/7

DENIUS [597]

it would be 35/3 or 11 2/3

4 0

3 years ago