Answer:
-x + 18
Step-by-step explanation:
just add 16 and 2. this is the furthest it can be simplified
1) Formula: area = height * base / 2
2) Call x the height:
height = x
base = 2x
3) State the equation:
(x)(2x) = 49 in^2
4) Solve the equation:
2x^2 = 49 in^s
x^2 = (49/2) in^2
x = √(49/2) in
x = 7√2 / 2 in = 3.5 √2 in
5) Solution:
height = 3.5 √2 in and base = 7√2 in
6) Verification: area = (7√2 in) (3.5√2 in) = 49 in^2
Answer: height = 3.5√2 in and base = 7√2 in.
Answer : option A
To find the range of scores that represents the middle 50 % of the student who took the test , we find inter quartile
Inter quartile range is the middle 50% of the given range of scores.
The difference between the upper quartile and lower quartile is the inter quartile that is middle 50%
From the diagram , we can see that
Upper quartile = 89
lower quartile = 65
So range is 65% to 89%
Angle 4 would be 77degrees because angle two is vertical to angle four.
Angle 3 and Angle 1 are equal because they are vertical to each other.
You would subtract 180 (degrees) minus 77 (degrees) and get 103 (degrees).
So Angle 3 and Angle 1 would both be 103 degrees.
You would get 180 degrees from the line.
Answer:
Type I error.
Step-by-step explanation:
The decision to shut the process is triggered by the conclusion that the average height is significantly different from 66 mm.
This means that the null hypothesis, that states that the average height is not significantly different from 66 mm (μ=66), has been rejected.
If the null hypothesis is rejected, the error that can have been made is to reject a true null hypothesis, when the process is functioning to specification and the average length is not significantly different from 66.
This is a Type I error, that happens when a true null hypothesis is rejected.
