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3 years ago

What is 50/277 decimal to the nearest hundredth?

Mathematics

1 answer:

AfilCa [17]3 years ago

8 0

Answer:

50/277 is also the same as 50 ÷ 277, so just divide those two numbers.

50 ÷ 277 = 0.181

Now we find out 0.181 to the nearest hundredth

To the nearest hundredth when rounding the answer will be 0.18

So your answer is 0.18

Hope I helped! :)

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A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = - 16t^2 + 48t where t equals t

andriy [413]

Answer:

x = 3/2

The axis of symmetry is located at the vertex,

which is the also the highest point in this problem...

the x component of the vertex can be calculated as -b/2a = -48/-32 = 24/16 = 6/4 = 3/2

x = 3/2

Step-by-step explanation:

8 0

3 years ago

Find the volume of each sphere. Round to the nearest tenth.

bazaltina [42]

Answer:

267946.7

Step-by-step explanation:

here's the formula

V=4 /3πr3

3 0

4 years ago

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The parking rates at the hospital’s parking garage are 50 cents for the first hour and 25 cents for each additional hour. If Jua

Bad White [126]

The total charge for Juan in the parking spot would be $2.25.

Since we know one of those 8 hours is 50 cents, we can multiply .25 by 7 which would give us 1.75. Then we know that the first hour, as stated above, is going to be .50, so we can add that to our total which is 2.25.

Hope this helps!

3 0

4 years ago

Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф

asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B) = (A ∩ B) (Addition to zero identity property)

∴ A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅ ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0

3 years ago

WORDED QUADRATIC EQUATION!!! PLS HELP <br><br> MOSTLY NUMBER 5 PLS

pav-90 [236]

Answer:

7,11

Step-by-step explanation:

The width is x. x+4= the length. The area is side times side, so it’s

x × (x+4) = 77

We can simplify this to:

x × x + x × 4 = 77

x^2 + 4x = 77

x^2 + 4x - 77 = 0 This is a quadratic equation. So we can solve using the quadratic formula:

x = $\frac{-4\pm\sqrt{4^2-4\cdot1\cdot-77}}{2\cdot1}$ ->

$\frac{-4\pm18}{2}$

$\frac{14}{2} \implies7$

That’s the positive solution and that’s x, the width. So the width is 7 and the length is 7+4=11

3 0

2 years ago