Answer:
The expected cost of the company for a 3000 tires batch is $120255
Step-by-step explanation:
Recall that given a probability of defective tires p, we can model the number of defective tires as a binomial random variable. For 3000 tires, if we have a probability p of having a defective tire, the expected number of defective tires is 3000p.
Let X be the number of defective tires. We can use the total expectation theorem, as follows: if there are 
events that partition the whole sample space, and we have a random variable X over the sample space, then
.
So, in this case, we have the following
.
Let Y be the number non defective tires. then X+Y = 3000. So Y = 3000-X. Then E(Y) = 3000-E(X). Then, E(Y) = 2949.
Finally, note that the cost of the batch would be 40Y+45X. Then
The question is incomplete. Here is the complete question
It was estimated that because of people switching to Metro trains about 33000 of CNG 3300 tons of diesel and 21000 tons of petrol was saved by the end of year 2007 (I) find a fraction of the quantity of diesel saved to the quantity of petrol saved (ii) find the quantity of cng to the quantity of diesel saved
Answer:
(I) 11/70
(II) 1/10
Step-by-step explanation:
Metro trains contain 330,000 tons of CNG
3300 tons of diesel was saved
21000 tons of petrol was saved at the end of 2007
(I) The fraction of the quantity of diesel saved to the quantity of petrol saved can be calculated as follows
= 3300/21000
= 11/70
(II) The fraction of the quantity of CNG saved to the quantity of diesel can be calculated as follows
= 3300/33000
= 1/10
Answer:
the answer is D
Step-by-step explanation:
the answer is 14 or D
brainly would be epic
Answer:
We know that C is the total number of cans in a complete case.
Victoria counts:
16 full cases, so in those we have: 16*C cans.
4 cases with 5 missing cans, so in those we have:
Then if each case has C cans, the cases that are missing 5 cans have:
C - 5 cans.
Then in those four cases we have a total of: 4*(C - 5) cans.
And Victoria knows that there are 220 cans, then we have that:
16*C + 4*(C - 5) = 220
16*C + 4*C - 20 = 220
16*C + 4*C = 220 + 20 = 240
20*C = 240
C = 240/20 = 12
Then each case has 12 cans.
Then the number of cans in the cases with missing cans is:
12 cans - 5 cans = 7 cans.
