Rewrite <span>2cos x + 1 = 0 as:
2 cos x = -1, and then cos x = -1/2
x must be in Quadrant II or Quadrant III, since the adj. side is negative.
Note that the angle 120 has adj. side -1 and hyp 2. So 120 degrees is one solution.
Now what about a possible 2nd solution, to be found in Quadrant III? That would be -120 degrees, which has the same terminal line as does 240 degrees.
No soap.
So, the solution is 120 degrees.</span>
9514 1404 393
Answer:
12/x^5
Step-by-step explanation:
The fractions are multiplied in the usual way. The applicable rule of exponents is ...
(x^a)(x^b) = x^(a+b)
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Answer:
becuae he couldent see sorry i had to do that
Answer:
495 meter²
Step-by-step explanation:
In the given kite QRST,
PQ = PS = 15 meter
QR = 17 meter
We have to find the area of the kite.
Since kite is in the form of a rhombus.
and rhombus is = 
(Diagonal QS) × (Diagonal RT)
In Δ QRP,
17² = 15² + RP²
= √64 = 8 meters.
So RT = RP + PT = 8 + 25 = 33 meter.
Now area of kite = (30) (33) = 495 meter²
Answer:
Option D, x = 4
Step-by-step explanation:
Option A: y = 4 doesn't work because that line would be horizontal
Option B: y = 4x doesn't work because that would be diagnol
Option C: x = -4 doesn't work because that would a vertical line at -4
<em>Option D: x = 4 works because that would a vertical line at 4</em>
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Answer: Option D, x = 4
