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2 years ago

As an estimation we are told 5 miles is 8 km. Convert 60 miles to km

Mathematics

1 answer:

noname [10]2 years ago

8 0

Answer:

60 miles to km would be 0.06 kilometer.

Step-by-step explanation:

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The weight distribution of parcels sent in a certain manner is normal with mean of 12 lb and standard deviation of 3 lb. The par

kicyunya [14]

Answer:

21.16

Step-by-step explanation:

Starting from the theory we have the following equation:

$fi*P(x$

Using the data supplied in the exercise, we have subtracting the mean and dividing by the standard deviation:

$P( z \leq \frac{c-1-12}{3.5}) =0.99/fi$

solving for "c", knowing that fi is a tabulating value:

$\frac{c-13}{3.5}=0.99/fi\\\frac{c-13}{3.5}=2.33\\c-13=2.33*3.5\\c = 8.155 +13\\c = 21.155$

therefore the value of c is equal to 21.16

8 0

3 years ago

VERY IMPORTANT I NEED HELP!!!

Advocard [28]

Answer:

2√3

Step by step Explanation:

$= > \frac{ \sqrt{96} }{ \sqrt{8} } \\ \\ = > \frac{ \sqrt{12 \times 8} }{ \sqrt{8} } \\ \\ = > \frac{ \sqrt{12} \times \sqrt{8} }{ \sqrt{8} } \\ \\ = > \sqrt{12} \\ \\ = > \sqrt{4 \times 3} \\ \\ = > \sqrt{2 \times 2 \times 3} \\ \\ = > 2 \sqrt{3}$

3 0

3 years ago

1 - 3x = 3x + 1 solve for x

lakkis [162]

Answer: x = 0

Step-by-step explanation:

1 - 3x = 3x + 1

then add 3x on both sides

1 = 6x + 1

then subtract 1 on both sides

0 = 6x

then divide by 6 on both sides

0 = x

so x = 0

3 0

3 years ago

Read 2 more answers

What is the number 1,340,000 from standard form to scientific notation

Kisachek [45]

6 1.34*10 Just move it to the left 6 times

7 0

3 years ago

Read 2 more answers

At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean

GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean. Draw a normal curve and mark these speeds. 115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145. This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area: normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573. In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

8 0

2 years ago