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7nadin3 [17]
3 years ago
14

Points A and B lie on a circle with radius 1, and arc AB ⌢ has a length of

7D%7B3%7D" id="TexFormula1" title="\frac{\pi }{3}" alt="\frac{\pi }{3}" align="absmiddle" class="latex-formula">. What fraction of the circumference of the circle is the length of arc AB ⌢?
Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0

Answer:

0.167

EXPLANATION:

To figure out the answer to this question, you'll first need to know the formula for finding the circumference of a circle.

The circumference, C, of a circle is C=2πr, where r is the radius of the circle. For the given circle with a radius of 1, the circumference is C=2(π)(1), or C=2π.

To find what fraction of the circumference the length of AB⌢ is, divide the length of the arc by the circumference, which gives \frac{\pi }{3}÷2\pi.

This division can be represented by \frac{\pi }{3}×\frac{1}{2}\pi =\frac{1}{6}

can also be rewritten as 0.166 or 0.167.

Triss [41]3 years ago
4 0

Answer:

Solution given:

arc AB :angle=\frac{\pi }{3}=60

radius[r]=1

Now

we have

<u>Circumference</u><u> </u><u>the circle is the length of arc AB ⌢</u>:\frac{arc AB }{360}2\pi*r

:

\frac{180}{3}    \div 360 \times 2\pi \:  \times 1

=⅓π or 1.047units

<u>N</u><u>o</u><u>t</u><u>e</u><u>:</u>

<u>F</u><u>o</u><u>r</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>π</u><u>=</u><u>1</u><u>8</u><u>0</u>

<u>F</u><u>o</u><u>r</u><u> </u><u>l</u><u>e</u><u>n</u><u>g</u><u>t</u><u>h</u><u> </u><u>π</u><u>=</u>\frac{22 }{7}.

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Answer: Simplifying ratios is just like simplifying fractions. Think of ratios as fractions. You divide a number that both numerator and denominator can be divided by.

<u>Example</u>

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How did we get 1/2? Simple! You divide the numerator and denominator by 5.

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You do the same for ratios but the only difference is instead of putting a fraction bar (/) you put a colon (:)

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<u>Remember</u>

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