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7nadin3 [17]
3 years ago
14

Points A and B lie on a circle with radius 1, and arc AB ⌢ has a length of

7D%7B3%7D" id="TexFormula1" title="\frac{\pi }{3}" alt="\frac{\pi }{3}" align="absmiddle" class="latex-formula">. What fraction of the circumference of the circle is the length of arc AB ⌢?
Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0

Answer:

0.167

EXPLANATION:

To figure out the answer to this question, you'll first need to know the formula for finding the circumference of a circle.

The circumference, C, of a circle is C=2πr, where r is the radius of the circle. For the given circle with a radius of 1, the circumference is C=2(π)(1), or C=2π.

To find what fraction of the circumference the length of AB⌢ is, divide the length of the arc by the circumference, which gives \frac{\pi }{3}÷2\pi.

This division can be represented by \frac{\pi }{3}×\frac{1}{2}\pi =\frac{1}{6}

can also be rewritten as 0.166 or 0.167.

Triss [41]3 years ago
4 0

Answer:

Solution given:

arc AB :angle=\frac{\pi }{3}=60

radius[r]=1

Now

we have

<u>Circumference</u><u> </u><u>the circle is the length of arc AB ⌢</u>:\frac{arc AB }{360}2\pi*r

:

\frac{180}{3}    \div 360 \times 2\pi \:  \times 1

=⅓π or 1.047units

<u>N</u><u>o</u><u>t</u><u>e</u><u>:</u>

<u>F</u><u>o</u><u>r</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>π</u><u>=</u><u>1</u><u>8</u><u>0</u>

<u>F</u><u>o</u><u>r</u><u> </u><u>l</u><u>e</u><u>n</u><u>g</u><u>t</u><u>h</u><u> </u><u>π</u><u>=</u>\frac{22 }{7}.

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in 2013 January there were 360 pupils in school the ratio of boots to girls was 5:4 in February 18 boys were admitted in school
anyanavicka [17]

Answer:

218

Step-by-step explanation:

this is ratio.

5+4=9. which is the ratio you add it.

5/9×360=200

therefore the number of boys in school during 2013 january is 200 plus admitted boys in February is 200+18=218.

therefore the number of boys in school from january to february is 218.

5 0
3 years ago
Select the correct answer from each drop-down menu
Yakvenalex [24]

Answer:

First row. = -393 74 287

Second row = 471. 162 91

Third row =251 222 - 349

Step-by-step explanation:

For the first row

Cofactor of 12= (-8*15)-(21*13)

= -120-273

= -393

Cofactor of 23 = (11*15)-(7*13)

= 165-91

= 74

Cofactor of -6 = (11*21)-(-7*8)

= 231+56

= 287

For the second row

Cofactor of 11 = (23*15)-(21*-6)

= 345+126

= 471

Cofactor of -8 = (12*15)-(7*-6)

= 120 + 42

= 162

Cofactor of 13 (12*21)-(23*7)

= 252-161

= 91

For third row

Cofactor of 7= (23*13)-(-8*-6)

= 299-48

= 251

Cofactor of 21 = (12*13)-(11*-6)

= 156+66

=222

Cofactor of 15 = (12*-8)-(11*23)

= -96 - 253

=- 349

8 0
3 years ago
Why must fire extinguishers be routinely maintained?
eduard

Answer: the answer would be To make sure they remain effective.

Step-by-step explanation:

It wouldn't be to make sure they are up to code because fire extinguishers do not use code, code is used in electronics. For the second option and the last option it would not be this because they could be trained in a practice instead of using the real thing.

7 0
3 years ago
Read 2 more answers
2y = 4x - 8<br> y = x +4<br> Solve by substitution
Nataly [62]

Answer:

x=8

Step-by-step explanation:

2(x+4)=4x-8

2x+8=4x-8

2x+8-8=4x-8-8

2x=4x-16

2x-4x=4x-16-4x

-2x=-16

Divide by -2 on both sides

and get... X=8

3 0
3 years ago
600 is how many times as much as 20?
Montano1993 [528]

The value 600 is 30 times as much as 20

<h3>Ratio and proportion</h3>

Ratio are written in terms of fractions. The expression 600 is how many times as much as 20 can be written as;

600 = x *20

where x is the required value or factor

20x = 600

Divide both sides by 20

20x/20 = 600/20

x = 30

Hence the value 600 is 30 times as much as 20

Learn more on ratio and proportion here: brainly.com/question/19994681

#SPJ1

3 0
2 years ago
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