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jeka57 [31]
3 years ago
7

Can someone please help with this and show me in steps will give brainliest?​

Mathematics
1 answer:
alina1380 [7]3 years ago
5 0
A. 3 times 10^4
90000000 divided by 3000 is 30000 which happens to be equal to 3 times 10^4

If you want to learn how to do this just take your whole number ex: 3 and put 10^6 and you will have 3 followed by 6 zeros. The ^ is just how many zeros will follow your whole number at first.
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Units of Length
grin007 [14]

the answer is:

78.7 (i rounded it to the nearest tenth)

7 0
3 years ago
The expression 100−2.5x represents the balance of Grace’s lunch account after x days. The expression 100+2.5(5−x) represents the
Mars2501 [29]

Answer:

Step-by-step explanation:

That means that the given expressions are equal.

100 - 2.5x = 100 + 2.5(5 - x)

100 - 2.5x = 100 + 12.5 - 2.5x

There is no solution to this.

8 0
3 years ago
Find the equation of the line which passes through the point (−2,−5) and is parallel to the line −3x+5y=−4.
leonid [27]
-3x+5y=-4
5y=3x-4
Y=3/5x-4/5


When it parallel to the line y=3/5x-4/5

It can be y=-3/5x+b

-5=6/5+b

B=-5-6/5=-25/5-6/5=-31/5

Y=-3/5x-31/5

3/5x+y=-31/5

Multiply 5

3x+5y=-31
4 0
3 years ago
Read 2 more answers
Multiply. Enter your answer as a simplified mixed number. -4(3/14) ​
Rus_ich [418]

Answer:

-53 /14

Step-by-step explanation:

6 0
2 years ago
Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.
SSSSS [86.1K]

Answer:

  \dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

  -x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}

6 0
2 years ago
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