Question

A life insurance salesman sells on the average 4 life insurance policies per week.

Answer 1

Answer:

0.195

0.191

Step-by-step explanation:

Given that :

μ = 4

Using poisson :

P(x) = (e^-μ * μ^x) ÷ x!

P(x = 3) = (e^-4 * 4^3) / 3!

= (0.0183156 * 64) / 6

= 0.1953664

= 0.195

b. What is the probability that he will sell at most 5 policies in two weeks period?

Mean per week = 4

Mean in two weeks = 4 * 2 = 8

P(x ≤ 5) = p(5) + p(4) +... + p(0)

Using the poisson distribution calculator :

P(x ≤ 5) = 0.19124

= 0.191