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3 years ago

Is (3, 1) the solution of the system of equations shown below? 2x + 3y = 9 -2.c + y = -5

Mathematics

2 answers:

IrinaK [193]3 years ago

6 0

Yes it is (3,1) , you are correct

Sauron [17]3 years ago

4 0

Answer:

I love algebra anyways

The ans is in the picture with the steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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What kind of angles are they

Yuliya22 [10]

Answer:

Alternate Interior Angles

Step-by-step explanation:

The angles are on opposite sides of the transversal and are in between the parallel lines. This means they are alternate Interior Angles. Additionally, this means they are congruent, so 15x=12x+15, which gives us x=5, and the measurements of the angles are 75° each.

3 0

3 years ago

Sony brother is 8 year older than four fifth her age. if her brothers age is 32 years what is sony

madam [21]

Answer:

I would say Sony's age is 33 because 4/5 of 32 is about 25 then 25+8=33

Hope I helped :)

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3 years ago

Jerry buys a case of bar soap. The case holds 12 packages. Each package contains four bars of soap. If each bar of soap is four

Sonja [21]

Answer:

The answer is D. 12 pounds

Step-by-step explanation:

Math is not my strong suit, so I apologize if this is wrong.

7 0

3 years ago

Suppose a certain type of fertilizer has an expected yield per acre of mu 1 with variance sigma 2, whereas the expected yield fo

mart [117]

Answer:

See the proof below.

Step-by-step explanation:

For this case we just need to apply properties of expected value. We know that the estimator is given by:

$S^2_p= \frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2}$

And we want to proof that $E(S^2_p)= \sigma^2$

So we can begin with this:

$E(S^2_p)= E(\frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2})$

And we can distribute the expected value into the temrs like this:

$E(S^2_p)= \frac{(n_1 -1) E(S^2_1) +(n_2 -1) E(S^2_2)}{n_1 +n_2 -2}$

And we know that the expected value for the estimator of the variance s is $\sigma$ , or in other way $E(s) = \sigma$ so if we apply this property here we have:

$E(S^2_p)= \frac{(n_1 -1 )\sigma^2_1 +(n_2 -1) \sigma^2_2}{n_1 +n_2 -2}$

And we know that $\sigma^2_1 = \sigma^2_2 = \sigma^2$ so using this we can take common factor like this:

$E(S^2_p)= \frac{(n_1 -1) +(n_2 -1)}{n_1 +n_2 -2} \sigma^2 =\sigma^2$

And then we see that the pooled variance is an unbiased estimator for the population variance when we have two population with the same variance.

8 0

3 years ago

Can someone please explain to me how I'm supposed to solve 2x+y=12? Like step by step solving?

Ne4ueva [31]

Well, first put the function in slop-intercept form (y = mx + b). 2x + y = 12, y - 2x = 12 - 2x, y = -2x + 12. So y = -2x + 12 is the slope-intercept form. Then graph the function to solve for all possible solutions to the function. In y = mx + b, m is the slope and b is the y intercept. In y = -2x + 12, m equals -2, so the slope is -2, and b equals 12, so 12 is the y intercept. Make a point on the y intercept at y = 12. The slope is -2, or -2/1. The graph will be sloping downward. From the point at y = 12, move down two units and to the right one unit and make another point. Then from this new point move down two units and to the right one unit and make another point, and so on. Then to extend the graph in the other direction, start at the point y = 12 and move two units up and one unit to the right and make a point there. Then from this new point move two units up and one unit to the right and make another point there, and so on.

3 0

2 years ago