Question

Need steps for both questions

Answer 1

Answer:

$\large\boxed{Q10.\ y=2x-6}\\\boxed{Q12.\ y=-\dfrac{3}{7}x-2}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

Q 10.

$6x-3y=18$       subtract 6x from both sides

$6x-6x-3y=-6x+18$

$-3y=-6x+18$          divide both sides by (-3)

$\dfrac{-3y}{-3}=\dfrac{-6}{-3}x+\dfrac{18}{-3}\\\\y=2x-6$

Q 12.

$-3x-7y=14$            add 3x to both sides

$-3x+3x-7y=3x+14$

$-7y=3x+14$            divide both sides by (-7)

$\dfrac{-7y}{-7}=\dfrac{3}{-7}x+\dfrac{14}{-7}\\\\y=-\dfrac{3}{7}x-2$

Answer 2

11.

6x-3y=18

-3y=-6x+18

y = (-6x +18)/-3

y = 2x - 6

12.

-3x-7y=14

-7y=3x+14

y=(-3/7)x - 2