Answer:
- 11040 m³
- k ≈ 0.33
- V = (1/3)Bh
Step-by-step explanation:
The given relation is ...
V = kBh . . . . . for some base area B, height h, and constant of variation k
We are given length and width of the base so we presume it is a rectangle.
B = l·w = 8·11 = 88 . . . . square meters
The given volume tells us the value of k:
1144 = k(88)(39) . . . . . . cubic meters
1144/3432 = k = 1/3 ≈ 0.33
The value of k is about 0.33.
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Then the volume of the larger pyramid is ...
V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³
The general relationship is ...
V = 1/3Bh
Answer: Choice B) 128
Explanation:
We'll add up the given arc measures and then cut the result in half to get the angle formed by the intersecting chords (that subtend the arcs in question).
chord angle = (arc1+arc2)/2
x = (54+202)/2
x = 256/2
x = 128
Answer:
8² = 4² + 5² - 2(4)(5) cos(P)
which is the third option
Explanation:
The general rule of cosine is:
a² = b² + c² - 2bc*cos(A)
In our triangle:
a is substituted by p = 8 cm
b is substituted by n = 4 cm
c is substituted by m = 5 cm
A is substituted by P which we want to find
Replace the variables in the general equation with the givens as follows:
p² = n² + m² - 2mn*cos(P)
8² = 4² + 5² - 2(4)(5) cos(P)
Hope this helps :)
A tangent contains no chords
