Quadrilateral ABCD is translated 5 units right. What are the coordinates of quadrilateral

Mathematics

2 answers:

andreyandreev [35.5K]2 years ago

5 0

Answer:

it should be C sry if I'm wrong <3

zubka84 [21]2 years ago

5 0

Answer:

Step-by-step explanation:

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Sophia wanted to knit a scarf 1 meters long. On Monday, she knit

Sergio [31]

She knit 1/4 of the total length of the scarf on monday

Answer:

She knit 7/10 of the scarf altogether

Step-by-step explanation:

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3 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Mkey [24]

For this case, we have to:

By definition, we know:

The domain of $f (x) = \sqrt [3] {x}$ is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

$y = \sqrt [3] {x-2}$ with $x = 0$ : $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x+2}$ with $x = 0:\ y = \sqrt [3] {2}$ is also defined.

$f (x) = \sqrt {x}$ has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .