Question

9x^2-9x-18=0 so what will be ans​

Answer 1

Answer:

Step-by-step explanation:

Formula

$\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$

Givens

a = 9

b = - 9

c = -18

Solution

$\frac{- (-9) +/- \sqrt{(-9)^2 - 4*9*(-18)} }{2*9}\\\\\frac{9 +/- \sqrt{81 + 4*9*18} }{18} \\\\\frac{9 +/- \sqrt{ 81 + 288} }{18}$

9 +/- √369

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      18

9 +/- 3*√41

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      18

x = 9 +/- 19.209

     =========

        18

x = 1.567

or

x = -.567

Answer 2

Answer:

9x^2-9x-18=0

9x+2=11x-9x-18=0

9x+2=21x-18=0

9x+2=3x-3^=0