Answer:
I guess it is the Answer C
Answer:
415.63 minutes
Step-by-step explanation:
Growth can be represented by the equation 
. We can find the rate at which it grows by using t=25 minutes and 
or double the amount at that time. The first step we always take is to divide 
by A.
![[tex]\frac{A_{0}}{A}=e^{rt}\\2=e^{r(25)}](https://tex.z-dn.net/?f=%5Btex%5D%5Cfrac%7BA_%7B0%7D%7D%7BA%7D%3De%5E%7Brt%7D%5C%5C2%3De%5E%7Br%2825%29%7D)
To solve for r, we will take the natural log of both sides and use log rules to isolate r.
We know 
so we were able to cancel it out and divide both sides by 25.
We solve with a calculator 
We change 0.0277 into a percent by multiplying by 100 to get 2.77% as the rate.
The equation is 
.
We repeat the step above substituting A=5,000,000, =50, and r=0.02777. Then solve for t.
t=415.63 minutes
Answer:
D 36
Step-by-step explanation:
<em>Write the information algebraically</em>
c = 3a
c + a = 48
c = children, a = adults
<em>In the second sentence (in bold), we can replace c with 3a</em>
c + a = 48 → 3a + a = 48
<em>Simplify</em>
3a + a = 48 → 4a = 48 → a = 12 (divide both sides by 4)
<em>We can then substitute or plug in a = 12 into the original equation:</em>
c + a = 48 → c + 12 = 48 → c = 36 (subtract 12 from both sides)
<h3>There are 36 children</h3>
Answer:
1. k=1, b=1
2. k=-1, b=-0.5
Step-by-step explanation:
5/4 = 75/g....cross multiply because this is a proportion
5g = 300
g = 300/5
g = 60
so in 2nd semester, there were 75 students in art class and 60 students in gym class....for a total of 135 students.
1st semester....ratio was 2:7...added = 9
art : 2/9(135) = 270/9 = 30 <=== art class had 30
gym: 7/9(135) = 945/9 = 105 <=== gym class had 105
