You need to add up three things:
- two sides of 60" each (60*2=120")
- the perimeter of the upper semicircle (3.14*27/2=42.412")
- the perimeter of the lower semicircle (3.14*27/2=42.412")
After addition:
120+42.412+42.412=204.823"
I hope you got
the idea!
Answer:
58 = <1
Step-by-step explanation:
The sum of the opposite interior angles of a triangle is equal to the exterior angle
101 = 43+ <1
Subtract 43 from each side
101- 43 = <1
58 = <1
Since, the polygon is a trapezoid made up of a rectangle and a right triangle. Therefore, according to the question, the figure of the polygon is attached.
Since, perimeter is the total length of the outer boundary of the figure. Therefore,
Perimeter of the polygon is


Area of the polygon = Area of Rectangle + Area of Triangle
![=[(18) \times (15)] + [(\frac{1}{2}) \times (8) \times (15)]](https://tex.z-dn.net/?f=%3D%5B%2818%29%20%5Ctimes%20%2815%29%5D%20%2B%20%5B%28%5Cfrac%7B1%7D%7B2%7D%29%20%5Ctimes%20%288%29%20%5Ctimes%20%2815%29%5D)
![=270 + [(\frac{8}{2}) \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B%28%5Cfrac%7B8%7D%7B2%7D%29%20%5Ctimes%20%2815%29%5D)
![=270 + [4 \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B4%20%5Ctimes%20%2815%29%5D)


100/17 = 5.88 meters per second