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3 years ago

Please help me ppleaseeeeeee

Mathematics

1 answer:

asambeis [7]3 years ago

3 0

Answer: 1 < x < 13

Step-by-step explanation: 7-6 is 1 so 1 is the lowest and 7+6= 13 so 13 is the highest possibility for it still to be a triangle.

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describe the slopes of the parallel lines. Then, give an example of two linear equations that are parallel

Ivan

The slopes are the same.
Example: y=2x+5 & y=2x+7

3 0

3 years ago

The question is in the pic please be specific

vichka [17]

Box 1) (LxW) 20x6=120
box 2) (LxW) 15x4=60
box 1 cost) (size of box x price of box) 120x1.25=150
box 2 cost) (size of box x price of box) 60x1.25=75
subtract 150 and 75 to get 75

answer: the company is saving $75 by choosing to make 50 of box 2 instead of 50 of box 1

hope this makes sense comment if you need more explanation

8 0

3 years ago

A man walks due east for 4km, he then changes direction and walks on a bearing on a bearing of 197° until he is south west of hi

Fed [463]

Answer:

13.08 ≈ y

Step-by-step explanation:

7 0

3 years ago

A local library claims it has 2.73x103 books. If there are 42 people in the building, how many books per capita are there?

Marizza181 [45]

Answer:

63 books per capita in the library

Step-by-step explanation:

Given

$Books = 2.73 * 10^3$

$People = 43$

Required

Determine the book per capita

To do this, we simply divide the number of books by number of person;

$Average = \frac{Books}{People}$

$Average = \frac{2.73 * 10^3}{43}$

$Average = \frac{2.73 * 1000}{43}$

$Average = \frac{2730}{43}$

$Average = 63.488372093$

$Average = 63$ (Approximated)

Hence;

<em>There are 63 books per capita in the library</em>

7 0

3 years ago

What is the average rate of change of the function over the interval x = 0 to x = 5?

AURORKA [14]

$\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 2x^2-1\qquad \begin{cases} x_1=0\\ x_2=5 \end{cases}\implies \cfrac{f(5)-f(0)}{5-0} \\\\\\ \cfrac{[2(5)^2-1]~~-~~[2(0)^2-1]}{5}\implies \cfrac{50-(-1)}{5}\implies \cfrac{50+1}{5}\implies \cfrac{51}{5}\implies 10\frac{1}{5}$

6 0

3 years ago