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Nana76 [90]
3 years ago
6

Please help me ppleaseeeeeee

Mathematics
1 answer:
asambeis [7]3 years ago
3 0

Answer: 1 < x < 13

Step-by-step explanation: 7-6 is 1 so 1 is the lowest and 7+6= 13 so 13 is the highest possibility for it still to be a triangle.

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What is the height of an isosceles trapezoid, if the lengths of its bases are 5m and 11m, and the length of a leg 4m.
pashok25 [27]

Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,

AE=FD=\dfrac{AD-EF}{2}=\dfrac{AD-BC}{2}=\dfrac{11-5}{2}=3.

Consider right triangle ABE, by the Pythagorean theorem

AB^2=EB^2+AE^2,\\ \\4^2=3^2+EB^2,\\ \\EB^2=16-9=7,\\ \\EB=\sqrt{7}\ m.

Answer: \sqrt{7}\ m.

5 0
3 years ago
HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION!!!!
Bogdan [553]

Answer:

D

Step-by-step explanation:

Since it’s asking for numbers between -1 and 8 the equation cannot contain a equal symbol therefore it must be D

5 0
3 years ago
If r(x) = 3x - 1 and s(x) = 2x + 1, which expression is equivalent to (r/s)(6)?
Nana76 [90]

Answer:

Step-by-step explanation:

(r/s)(x) is the quotien of r(x) = 3x - 1 and s(x) = 2x + 1:

  r            3x - 1

(-----)(x) = ----------

  s            2x + 1

8 0
3 years ago
The differential equation of a certain system is 20⁢y′⁢′+c⁢y′+80⁢y=0
Sholpan [36]

Answer:

c=80

Step-by-step explanation:

Based on my reading the critical damping occurs when the discriminant of the quadratic characteristic equation is 0.

So let's see that characteristic equation:

20⁢r^2+c⁢r+80⁢=0

The discriminant can be found by calculating b^2-4aC of ar^2+br+C=0.

a=20

b=c

C=80

c^2-4(20)(80)

We want this to be 0.

c^2-4(20)(80)=0

Simplify:

c^2-6400=0

Add 6400 on both sides:

c^2=6400

Take square root of both sides:

c=80 or c=-80

Based on further reading damping equations in form

a⁢y′⁢′+b⁢y′+C⁢y=0

should have positive coefficients with b also having the possibility of being zero.

5 0
3 years ago
Find each function value.
Levart [38]

Put the values of x to the equations of the functions:

1. f(9) → x = 9; f(x) = -3x + 10

f(9) = -3(9) + 10 = -27 + 10 = -17

2. f(-2) → x = -2; f(x) = 4x - 1

f(-2) = 4(-2) - 1 = -8 - 1 = -9

3. f(-5) → x = -5; f(x) = -2x + 8

f(-5) = -2(-5) + 8 = 10 + 8 = 18

5 0
3 years ago
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