Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:
<em>y</em> = -1 - <em>x</em> ==> <em>x</em> = -1 - <em>y</em>
<em>y</em> = <em>x</em> - 1 ==> <em>x</em> = 1 + <em>y</em>
So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.
This means the area is given by the integral,
The integral with respect to <em>x</em> is trivial:
For the remaining integral, integrate term-by-term to get
Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.
X=65 y=49 z=114 w= 93 t=86
That's how I would graph it...
4(2m-n)-3(2m-n)
4(2(-15)- -18)-3(2(-15)- -18)
4(-30- -18)-3(-30- -18)
4(-12) -3(-12)
-48- -36
-12
The answer is C
Answer:
combine -3-1
if you want to solve for x then you would move the -14 to the left buy adding 14 to both sides.
your equation there will be
then you will divide -2 on both sides
finally x will equal