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KATRIN_1 [288]
3 years ago
12

Write an algebraic rule for the trend line. Report your rule in slope intercept form.

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0

Answer:

y = 5x + 20

Step-by-step explanation:

Here, we want to find the slope intercept form equation of the trend line

The general form is:

y =

mx + b

b is slope and m

is the y-intercept

b = 20

To get the slope, we select any two points and use the slope formula

we have the points;

(10,70) and (5,45)

The slope formula is;

m = (y2-y1)/(x2-x1) = (45-70)/(5-10) = -25/-5 = 5

The equation of the line is thus;

y = 5x + 20

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kiruha [24]

Answer:

x = 2π3

Step-by-step explanation:

csc(x)csc(x) , x=πx=π

3x+2y+zx+y+z3x+2y+zx+y+z , x=2x=2 , y=3y=3 , z=1z=1

cot(3x)cot(3x) , x=2π3

Hope this helps :)

8 0
3 years ago
What is the sum of complex numbers 2+3i and 4+8i, where i= square root -1
bearhunter [10]

Answer:

6+11i

Step-by-step explanation:

2+3i  +  4+8i

Add the real parts

2+4 = 6

And the imaginary parts

3i+8i = 11i

The complex number is the real plus the imaginary

6+11i

3 0
3 years ago
If P(x) = P<img src="https://tex.z-dn.net/?f=_%7Bn%7D" id="TexFormula1" title="_{n}" alt="_{n}" align="absmiddle" class="latex-f
seropon [69]

If P(x) = p_nx^n + p_{n-1}x^{n-1}+\ldots+p_0 is divided by (x-a), then P(x) = (x-a) \cdot Q(x) + R(x) for some polynomials Q,R. Moreover, \deg R < 1 (because \deg (x-a) = 1), so there exists  \alpha \in \mathbb{R} such that R(x) = \alpha for all x \in \mathbb{R}. But if we calculate P(a), it turns out that P(a) = (a-a)\cdot Q(a) + \alpha, so R(x) = \alpha = P(a). \blacksquare

3 0
3 years ago
I forgot to do slopes
Minchanka [31]
To find the slope of the line, use the rise over run formula:

\frac{y_{2} - y_{1}}{x_{2} - x_{1}}

Take any two points from the line and plug them into the formula.

(0,0) and (10, 5)

\frac{5 - 0}{10 - 0} = \frac{5}{10} = 0.5

The slope of the line is 0.5.

Using the form y = mx, the following equation will be your answer:

y = 0.5x
7 0
3 years ago
What is the length of AC?
sladkih [1.3K]
When the question says that triangle ABC ~ triangle DEF, that means the triangles are similar. This means that their proportions are the same.
In triangle ABC, side length AB is the equivalent of side length DE in triangle DEF.

Since the proportions must be the same, we can take the known side from triangle ABC, find the equivalent of it on triangle DEF, and find the proportions.
We already found that side length AB ~ side length DE.
Now we can divide the lengths to find the proportions.
28 / 8 = 3.5
This means that each side on triangle ABC will be 3.5 times greater than the equivalent side on triangle DEF.

The length of AC in triangle ABC is 3.5 times the length of DF in triangle DEF.
Side length DF is 10.
Multiply 3.5 by 10 to get the length of AC.
3.5 • 10 = 35
So the length of AC is 35 units.

Answer:
Side length AC in triangle ABC is 35 units.

Hope this helps!
7 0
4 years ago
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