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netineya [11]
2 years ago
10

How much energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C?

Chemistry
1 answer:
USPshnik [31]2 years ago
7 0

Answer:

1540.8 Joules of energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C

Explanation:

Crayon is paraffin wax. The specific heat of paraffin wax is 2.14 J/g°C

As we know

Q = m*c *\Delta T

Where

\Delta T is the change in temperature T_2- T_1

m is the mass of the object

c is the specific heat in J/g°C

Substituting the given values, we get -  

Q = 30 * 2.14 *(49-25)\\Q = 1540.8    Joules

1540.8 Joules of energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C

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The given question is incomplete, the complete question is:

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?

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Explanation:

There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.  

The no. of moles can be determined by using the formula,  

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