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Anton [14]
3 years ago
11

Can someone help me with this?

Chemistry
2 answers:
kompoz [17]3 years ago
7 0

Easy. #2, Move fast, and are far apart because it's a gas. Gasses do not take the shape of any object like a liquid does, and can not be picked up with hands like a solid can

dolphi86 [110]3 years ago
5 0

The answer would have to be “move fast and far apart.”

I really hope this helps you.

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Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict wheth
Elena-2011 [213]

Answer:

\Delta S_{surr} = + 0.32113\: kJ/K

Explanation:

Given: Entropy of surrounding: ΔSsurr = ?

Temperature: T= 355 K

The change in enthalpy of reaction: ΔH = -114 kJ

Pressure: P = constant

As we know, ΔH = -114 kJ ⇒ negative

Therefore, the given reaction is an exothermic reaction

Therefore, Entropy of surrounding at <em>constant pressure</em> is given by,

\Delta S_{surr} = \frac{-\Delta H}{T}

\therefore \Delta S_{surr} = -\left (\frac{-114 kJ}{355 K}  \right ) = + 0.32113\: kJ/K > 0

<u><em>In the given reaction:</em></u>

2NO(g) + O₂(g) → 2NO₂(g)

As, the number of moles of gaseous products is less than the number of moles of gaseous reactants.

\therefore \Delta S_{system} <  0

As we know, <em>for a spontaneous process, that the total entropy should be positive.</em>

\Delta S_{total} = \Delta S_{surr} + \Delta S_{system} > 0  

<u>Therefore, at the given temperature,</u>

  • if \Delta S_{surr} > \Delta S_{system} \Rightarrow \Delta S_{total} > 0 then the given reaction is spontaneous
  • if \Delta S_{surr} < \Delta S_{system} \Rightarrow \Delta S_{total} < 0 then the given reaction is non-spontaneous
6 0
3 years ago
The electrolysis of water has the equation 2H2O (l) → 2H2 (g) + O2 (g). What type of reaction is this?
OverLord2011 [107]

Answer:b

Explanation:

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Phosphorus-32 has a half-life of 14.0 days. Starting with 6.00 g of 32P, how many grams will remain after 42.0 days ?
aleksandrvk [35]
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After 42 days 0,75g of Phoshorus-32 will remain.
4 0
2 years ago
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Nicotine is an addictive substance found in tobacco. Identify the hybridization state and geometry of each of the nitrogen atoms
Marina CMI [18]

The structure of nicotine is as follows:

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Therefore, hybridization state of N^{1} and N^{2} (as in the attached structure) is sp^{2} and sp^{3} respectively.

Now, according to VESPR theory for sp^{2} hybridization with one lone pair the geometry is bent and for sp^{3} hybridization with one lone pair the geometry is pyramidal.

Therefore, geometry of N^{1} and N^{2} (as in the attached structure) is bent and pyramidal respectively.

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3 years ago
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madam [21]
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