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Anna71 [15]
3 years ago
15

What is the common name of sodium bicarbonate

Chemistry
1 answer:
Luba_88 [7]3 years ago
7 0

Answer: Baking soda

Explanation:

Sodium bicarbonate has a chemical formula of NaHCO3, it is a white precipitate formed when excess carbon dioxide is bubbled through a concentrated solution of sodium hydroxide.

It is used in cooking and serves as baking powder.

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Im teaching myself chemistry and need a guide. anyone game?
strojnjashka [21]
Which grade would u like to begin with? I can probably help with grade 9 Intro to Chemistry and Grade 10 Naming elements and compounds. That's all
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3 years ago
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3241004551 [841]

Answer:

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Explanation:

5 0
3 years ago
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Calculate the volume of a box with the following dimensions: length=8 cm
wel

Answer:  240 cm³

Explanation:

Volume of the box = l × w × h

                               = (8 cm × 6 cm × 5 cm)

                               = 240 cm³

8 0
2 years ago
How many grams are in 11.9 moles of chromium?
raketka [301]

Explanation:

It is known that one mole of chromium or molar mass of chromium is 51.99 g/mol.

It is given that number of moles is 11.9 moles.

Therefore, calculate the mass of chromium in grams as follows.

     No. of moles = \frac{mass in grams}{Molar mass}

    mass in grams = No. of moles × Molar mass

                             = 11.9 moles × 51.99 g/mol

                             = 618.68 g

Thus, we can conclude that there are 618.68 g in 11.9 moles of chromium.

7 0
3 years ago
Read 2 more answers
How many grams of CH4 will be in a 500ml contain at STP?
ArbitrLikvidat [17]

Answer:

Mass = 0.32 g

Explanation:

Given data:

Mass of CH₄ = ?

Volume of CH₄ = 500 mL (500 mL× 1L/1000 mL= 0.5 L)

Temperature = 273 K

Pressure = 1 atm

Solution:

Volume of CH₄:

500 mL (500 mL× 1L/1000 mL= 0.5 L)

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm× 0.5 L = n×0.0821 atm.L/ mol.K  × 273 K

0.5 atm.L = n×22.4 atm.L/ mol

n = 0.5 atm.L / 22.4 atm.L/ mol

n = 0.02 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.02 mol × 16 g/mol

Mass = 0.32 g

7 0
3 years ago
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