Sorry, I can't really see the question )-:
Given :
Molarity of acetic acid solution, M = 0.10 M.
pKa of acetic acid, pKa = 4.75 .
To Find :
Percentage dissociation of 0.10 M solution of acetic acid.
Solution :
We know, 
Taking antilog both side, we get :
Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.
Now, percentage dissociation of monoprotic acid is given by :
Hence, this is the required solution.
Answer:
Both have infinite range i believe
Explanation:
After the addition of 6.47 mL of 0.303 M HCl. Solution :- lets first calculate the moles of the NaOCl and HCl Moles = molarity *volume in liter Moles of NaOCl = 0.100 mol per L * 0.053 L =0.0053 mol Moles of HCl =0.303 mol per L *0.00647L=0.00196
Answer:
A star begins its life as a cloud of dust and gas (mainly hydrogen) known as a nebula. A protostar is formed when gravity causes the dust and gas of a nebula to clump together in a process called accretion. ... If a critical temperature in the core of a protostar is reached, then nuclear fusion begins and a star is born.
Explanation:
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