Answer:
7
Explanation:
This question is a neutralization reaction.
50 ml of 0.125 M of KOH = (50 x 0.125) = 6.25 ml
In this same way, 50 ml of 0.125M of HCl = 50x0.125
= 6.25 ml
Then KOH is going to neutralise the HCl fully suvh that the pH of the medium is going to be 7
(H+) + (OH-) = H2O
Then Kw = [H=][OH-]
= [H+]² = 10^-14
Such that [H+] = 10^-7
The pH would be = -log [H+]
= -log[10^-7]
When inputted on a calculator this gives us 7
= 7
This is our answer
Answer:
2522g
Explanation:
8Fe + S8 —> 8FeS
From the question,
8moles of Fe required 1mole of S8.
Therefore, Xmol of Fe will require 5.65mol of S8 i.e
Xmol of Fe = 8 x 5.65 = 45.2moles
Now we need to covert 45.2moles to gram. This is illustrated below below:
Molar Mass of Fe = 55.8g/mol
Number of mole of Fe = 45.2moles
Mass of Fe =?
Mass = number of mole x molar Mass
Mass of Fe = 45.2 x 55.8
Mass of Fe = 2522g
Therefore, 2522g of Fe is needed for the reaction.
3 bc Hf is an element hafnium and HF is compound hydrogen flouride
Hey there: !
density = 19.32 g/cm³
mass = 54.82 g
Volume = ?
therefore:
D = m / V
19.32 = 54.82 / V
V = 54.82 / 19.32
V = 2.837 cm³
The answer is water is a compound