1 electron=1 negative charge
lose 2 electrons= lose 2 negative charges
0-(-2)=+2
<u>Ca2+</u>
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Answer:
0.1688L of the 1M NaOH stock solution
Explanation:
A 215mM = 0.215M solution of NaOH contains 0.215 moles per liter. As you want to prepare 785mL = 0.785L of the 0.215M you will need:
0.785L × ( 0.215mol / L) = 0.1688 moles of NaOH.
<em>These moles of NaOH comes from the 1M stock solution</em>, that means the volume of 1M NaOH solution you need is:
0.1688 moles NaOH × (1L / 1mol) =
<h3>0.1688L of the 1M NaOH stock solution</h3>