<u>1</u><u> </u><u>1</u><u>\</u><u>2</u><u>. </u><u> </u><u>s</u><u>o</u><u> </u><u>h</u><u>e</u><u> </u><u>h</u><u>a</u><u>d</u><u> </u><u>t</u><u>h</u><u>a</u><u>t</u><u> </u><u>f</u><u>r</u><u>a</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>a</u><u>s</u><u> </u><u>a</u><u>l</u><u>l</u><u> </u><u>a</u><u>f</u><u>t</u><u>e</u><u>r</u>
Answer:
Step-by-step explanation:
Sin58 = opp/hyp
Sin58 = CB/14
CB = 14 × sin58°
CB = 11.9cm
1. 330,400
2. 0.000084
3. 2,100
4. 7.823 x 10^9
The answer is C
First you would start at the origin then move 3 units to the right then move 6 units up then that is your point