A. physical
B. Chemical
C.Physical
First you need to know the value of Kp for this reaction. The reaction is: SO2 (g) + 2 H2S (g)<=> 3S(s) + 2 H2O(g): Kp = PH2O^2 / PSO2(PH2O)^2 but since the problem is lacking in details.
Otherwise, let x = PSO2 = PH2S. Then:
Kp = (22/760 atm)^2 / x^3
x = cube root (0.289)/Kp = PSO2
But if the kp is given, let us assume it is 8.0*10^15The solution would be:convert the given pressure of water to atm, which is: 0.029
Kp=P(H2O)^2/P(SO2)P(H2S)^2
8.0*10^15 = (0.029)^2/x^3
(8.0*10^15).(x^3)=8.41*10^-4
take the cube root of both sides(2.0*10^5).x = 9.439130*10^-2x = P (SO2) = 4.6*10^-7
Answer:
First slide:
1) diffusion
2)water
3)high
4)low
5)balance
Second slide:
1)movement
2)without
3)energy
4)high
5)low
6)equilibrium
<u><em>Final slide: </em></u>
<u><em>1)passive</em></u>
<u><em>2)energy </em></u>
<u><em>3)randomly</em></u>
<u><em>4)high</em></u>
<u><em>5)low</em></u>
<u><em>6)equilibruim </em></u>
<u><em>7)permeable </em></u>
<u><em>8)Osmosis</em></u>
<u><em>9)water</em></u>
Hopes this helps! Good luck!