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3 years ago

I really need help on this one!!

Chemistry

1 answer:

Lady bird [3.3K]3 years ago

3 0

Answer:

Due to the decrease in the gravitational force, it will take longer time for ball to reach the ground while dribbling. Moreover, the hang time of players will also be longer. This means that the players will stay on air longer and will be able to jump higher.

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Which of the following is not a common hydrate. a epsom salt. b borax. c sugar. d alum

charle [14.2K]

Answer is option D that is ALUM.

6 0

4 years ago

Read 2 more answers

Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissol

Stells [14]

Here is the complete question.

Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissolves readily in water and polar organic solvents like ethanol. Calculate the mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol (CH3CH2OH; density = 0.7893 g/mol). Round to four significant digits

Answer:

0.9567 mol

Explanation:

Given that:

mass of glycerol = 1.61 g

molar mass of glycerol = 92.1 g/mol

no of mole = $\frac{mass}{molar mass}$

∴ number of moles of glycerol ( $n_{glycerol}$ ) = $\frac{1.61}{92.1}$

= 0.0175 mol

Volume of ethanol = 22.60 mL

Density of ethanol = 0.7893 g/mL

Since Density = $\frac{mass}{volume}$

∴ mass of ethanol = density of ethanol × volume of ethanol

mass of ethanol = 0.7893 g/mL × 22.60 mL

mass of ethanol = 17.838 g

Number of moles of ethanol $(n_{ethanol})$ = $\frac{17.838}{46.0684}$

= 0.387 mole

∴ the mole fraction of the solvent can be determined as:

$X_{solvent} = X_{ethanol} =$ $\frac{n_{ethanol}}{n_{glycerol}+n_{ethanol}}$

$=\frac{0.387 mol}{(0.0175+0.387)mol}$

$= \frac{0.387mol}{0.4045mol}$

= 0.95673671199

≅ 0.9567 mol

∴ The mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol is = 0.9567 mol

7 0

4 years ago

What is the arrangement of electron pairs of pbr3? predict the molecular shape of a pbr3 molecule?

mina [271]

Check the attached file for the solution. The shape is in the next file.

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4 years ago

How do you write out a science experiment

masha68 [24]

U need to do it in cronological order

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3 years ago

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Adenosine triphosphate (ATP) is the main energy currency used in cells. ATP hydrolysis is coupled with unfavorable reactions, ma

kotegsom [21]

Answer:

Thioesters- the Sulfur-Carbon bond is hydrolyzed, e.g. AcetylCoA

Reduced cofactor- These compounds accept electrons during the oxidation of substrates and energy is released when they are oxidized, e.g. Ubiquinol

Phosphorylated compounds- These compounds yield H₂P0₄⁻ upon hydrolysis, e.g. Phosphocreatine

Explanation:

Thioesters are esters in which the linking oxygen atom is replaced by a sulphur atom. They are the product of esterification between a carboxylic acid and a sulfhydryl group (thiol). They have the functional group R–S–CO–R'. Thioesters are common intermediates in many biosynthetic reactions. Examples include malonyl-CoA, acetyl-CoA, and propionyl-CoA. In the hydrolysis of thioesters, the sulfur-carbon bond is hydrolyzed.

Cofactors can be either organic or inorganic molecules that are required by enzymes to function. Cofactors can be oxidized or reduced for the enzymes to catalyze the reactions. Examples include, NAD, FAD, NADP, Coenzyme Q₁₀. Coenzyme Q₁₀ exists in three redox states, fully oxidized, partially reduced, and fully reduced. Ubiquinol is the reduced (electron-rich) form of coenzyme Q₁₀. Coenzyme Q₁₀ is vital for proper transfer of electrons within the mitochondrial oxidative respiratory chain, whose main function is to produce adenosine triphosphate (ATP). These compounds accept electrons during the oxidation of substrates and energy is released when they are oxidized.

Phosphorylated compounds are compounds with a phosphoryl group (PO₃²⁻) attached to its molecules. These compounds yield an inorganic phosphate (H₂P0₄⁻) upon hydrolysis. Phosphorylation is especially important for protein function as this modification activates or deactivates almost half of the enzymes, thereby regulating their function. Examples include, glucose-1-phosphate, phosphoserine, phosphocreatine, etc.

4 0

3 years ago