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natali 33 [55]
2 years ago
14

Under what conditions will a gas NOT obey Boyle's law ? There can be more than one correct answer.

Chemistry
1 answer:
Alenkasestr [34]2 years ago
7 0
PLEASE GO ANSWER MY LATEST QUESTION I NEED HELP
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Which bond is most polar?<br> ОА СО<br> ов So<br> Осно<br> ODNO
Romashka-Z-Leto [24]

Answer:

either first or second if not them try d but I'm pretty sure a also I'm sorry if I getbyou this wrong I dearly apologize

5 0
2 years ago
What is the concentration of a solution containing 1.11 g sugar (sucrose, C12H22O11, MW = 342.3 g/mol, d = 1.587 g/cm3) in 432 m
djyliett [7]

Answer:

0.0075 M

0.0060 m

Explanation:

Our strategy here is to use the definition of molarity and molality to solve this question.

The molarity is the number of moles of solute, sucrose in this case, per liter of solution.

The molality is the number of moles of solute per kilogram of solvent.

So the molarity of the  solution is

M = moles of solute/ V solution

As we see we need the volume of solution since we are only given the volume of solvent, but this will be easy to compute since we have the density of  sucrose.

So determine the moles of sucrose , and the volume of solution:

Moles sucrose = 1.11 g/342.3 g/mol = 3.24 x 10⁻³ M

Volume of solution = Vol Sucrose + Vol glycerine

d = m/V ⇒ Vsucrose = m / d = 1.11 g/ 1.587 g/cm³ = 0.70 cm³

Vol solution = 432 mL + 0.70 mL = 432.7 mL  (1cm³  = 1 mL)

Vol solution = 432.7 mL x 1 L / 1000 mL = 0.4327 L

⇒ M = 3.2 x 10⁻³  mol / 0.4327 L = 0.0075  M

For the molarity what we need is to first calculate the kilograms of glycerine from the given density:

d = m/v ⇒ m = d x v = 1.261 g/cm³ x  432 cm³ = 544.75 g

Converting to Kg:

544.75 g x 1 Kg/ 1000 g = 0.544 kg

Now the molality is

m = mol sucrose/ kg solvent = 3.24 x 10⁻³ mol / 0.544 Kg = 0.0060 m

Note: In the calculation for  volume of solution we could have approximated it to that of just glycerine, but since the density of sucrose was given we calculated the total volume of solution to be more rigorous.

8 0
3 years ago
What happens to concrete when it's no longer needed
Sveta_85 [38]
Did you mean when it is a liquid?
8 0
2 years ago
Use the periodic table to find the molar mass of
Naddika [18.5K]

I can give you a clue of getting mass. if it is the atomic number is even multiply by 2 but if the atomic number is odd multiply by 2 and add 1

sodium atomic number = 11 so mass = 11*2 +1 = 23

oxygen. atomic number = 8 so mass = 8*2 = 16

carbon atomic number = 6 so mass = 6*2 = 12

3 0
3 years ago
11. In TLC analysis of ferrocene and acetylferrocene (on silica TLC plate) which prediction is correct: A) ferrocene is more pol
yaroslaw [1]

Answer:

Alternative C would be the correct choice.

Explanation:

  • The dual compounds were evaluated on something like a TLC plate through three separate additives in conducting a TLC study of ferrocene versus acetylferrocene.
  • The polar as well as nonpolar ferrocene where nonpolar is about 0.63 with the maximum R_f value, and indeed the polar is somewhere around 0.19 with R_f.
  • TLC plate (30:1 toluene/ethanol) established with.  

The other three choices are not related to the given circumstances. So that option C would be the appropriate choice.

8 0
3 years ago
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