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natali 33 [55]
2 years ago
14

Under what conditions will a gas NOT obey Boyle's law ? There can be more than one correct answer.

Chemistry
1 answer:
Alenkasestr [34]2 years ago
7 0
PLEASE GO ANSWER MY LATEST QUESTION I NEED HELP
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2 years ago
What does carbon dioxide absorb the most heat energy
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Should be <span>during deposition.

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8 0
2 years ago
Try to rationalize the sign of ΔS∘rxn in each case.
bonufazy [111]

Answer:

a) decrease, gas

b) increase, gas

c) liquid

d) increase, solid

Explanation:

Entropy refers to the degree of disorderliness of a system. If the number of moles of gas increases from left to right in a reaction, the entropy of the system increases positively.

Similarly, when the number of liquid molecules remain constant, there could only be a very little increase in entropy.

However, solids have the least entropy and the entropy of a system decreases when a system yields solid products.

6 0
3 years ago
Which of the following acids should be used to prepare a buffer with a pH of 4.5?A. HOC6H4OCOOH, Ka = 1.0 x 10^-3B. C6H4(COOH)2,
ioda

Answer:

C. CH3COOH, Ka = 1.8 E-5

Explanation:

analyzing the pKa of the given acids:

∴ pKa = - Log Ka

A. pKa = - Log (1.0 E-3 ) = 3

B. pKa = - Log (2.9 E-4) = 3.54

C. pKa = - Log (1.8 E-5) = 4.745

D. pKa = - Log (4.0 E-6) = 5.397

E. pKa = - Log (2.3 E-9) = 8.638

We choose the (C) acid since its pKa close to the expected pH.

⇒ For a buffer solution formed from an acid and its respective salt, we have the equation Henderson-Hausselbach (H-H):

  • pH = pKa + Log ([CH3COO-]/[CH3COOH])

∴ pH = 4.5

∴ pKa = 4.745

⇒ 4.5 = 4.745 + Log ([CH3COO-]/[CH3COOH])

⇒ - 0.245 = Log ([CH3COO-]/[CH3COOH])

⇒ 0.5692 = [CH3COO-]/[CH3COOH]

∴ Ka = 1.8 E-5 = ([H3O+].[CH3COO-])/[CH3COOH]

⇒ 1.8 E-5 = [H3O+](0.5692)

⇒ [H3O+] = 3.1623 E-5 M

⇒ pH = - Log ( 3.1623 E-5 ) = 4.5

6 0
2 years ago
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