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natali 33 [55]
3 years ago
14

Under what conditions will a gas NOT obey Boyle's law ? There can be more than one correct answer.

Chemistry
1 answer:
Alenkasestr [34]3 years ago
7 0
PLEASE GO ANSWER MY LATEST QUESTION I NEED HELP
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Small children are occasionally injured when they try to inhale helium from
sattari [20]

Answer:

260 moles of Helium

Explanation:

V = 50L

T = 20°C = (20 + 273.15)K = 293.15K

P = 125 atm

R = 0.082 L.atm / mol. K

n = ?

From ideal gas equation,

PV = nRT

P = pressure of a given gas

V = volume it occupies

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

n = PV / RT

n = (125 * 50) / (0.082 * 293.15)

n = 6250 / 24.0383

n = 260.00 moles

The child inhaled 260 moles of Helium

8 0
3 years ago
Question 5 of 5
Romashka [77]

Answer:

A

Explanation:

l took the test

8 0
2 years ago
1. Which phase change is accompanied by the release of heat? A) H20(s)--> H2O(g) B) H20(l) ->H2O(s) C) H20(l)→ H2O(g) D) H
docker41 [41]

Answer:

B, liquid to solid.

Explanation: Since heat is being released, the particles for H2O would clump up. Heat is basically being taken out.

5 0
3 years ago
How can you find the number of neutrons that are in an atom of an element
Temka [501]

Answer:

You just have to take the periodic table of the elements, take the element that interests you. Then, you look at the formula of the element, at the top left you find the number of neutrons and protons and at the bottom left you find the number of protons. Then you just have to make the number from the top left minus the number from the bottom left.

Explanation:

4 0
3 years ago
The breaking buffer that we use this week contains 10mM Tris, pH 8.0, 150mM NaCl. The elution buffer is breaking buffer that als
olasank [31]

Answer:

A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula M_1*V_1 = M_2*V_2. It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL)  with water

Explanation:

Given data includes:

Tris= 10mM

pH = 8.0

NaCl = 150 mM

Imidazole = 300 mM

In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.

Stock Concentration             Volume to be             Final Concentration

                                               added            

1 M Tris                                     2.5 mL                         10 mM

5 M NaCl                                  7.5 mL                        150 mM

1 M Imidazole                           75 mL                         300 mM    

M_1*V_1 = M_2*V_2. is the formula that is used to determine the corresponding volume that is added for each stock concentration

The stock concentration of Tris ( 1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.01 M *250mL\\V_1 = 2.5mL

The stock concentration of NaCl (5 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.15 M *250mL\\V_1 = 7.5mL

The stock concentration of Imidazole (1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.03 M *250mL\\V_1 = 75mL

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.

5 0
3 years ago
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