Question

Consider the balanced chemical reaction below and determine the percent yield of sodium bromide if 2.36 moles of iron(iii) bromide yielded 6.14 moles of sodium bromide
2FeBr+3Na2S=Fe2S3+6NaBr

Answer 1

        First   the  theoretical yield   of Nabr
  by use  of  mole  ratio   between  FeBr3  and  NaBr  which  is  2:6   the   theoretical yield  

  =2.36  x6/2= 7.08  moles

the  %  yield  =  actual  yield/  theoretical  yield  x  100

that  is    6.14/7.08  x100=  86.72%

Answer 2

Answer:

86.72

Explanation:

Good luck