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3 years ago

I will mark Brainliest please help

Mathematics

1 answer:

Marizza181 [45]3 years ago

6 0

Answer:

f(x) = 2

Step-by-step explanation:

f(x) represents a linear function since it had the same first differences while the "x" values are evenly space out (which we know could happen only if the function is linear). Now that we determined that the function is linear we have to write the function as an expression.

We know that any linear function has a form of f(x) = mx + b, where "m" is the slope and "b" is the y intercept (y value when x is equal to 0).

As I already mentioned the b will be equal tp the "y" intersect which is equal to the "y" value when x is equal to zero. Luckily in our table they did tell us what will be the "y" value when x is equal to zero, and it is 2. So now we know b = 2.

Then we have have to find the slope which can be found by using the following formula.....

$m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }$

Now we have to choose two different points from table and let the one that has bigger x value be represented as $(x_{2} , y_{2} )$ and the other one will be represented as $(x_{1}, y_{1} )$ . In our case I choose the points (2,2) and (1,2). Now if we represent them as what I mentioned earlier we can substitute their values into the equation that we ca use to find the slope. You should obtain the following.....

$m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{2 -2}{2-1} = \frac{0}{1} = 0$

Now that we know both the "m" and "b" values we can substitute them into the equation, and we will get he following....

f(x) = mx + b

f(x) = 0x + 2

f(x) = 2

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Round to the nearest tenth.

laila [671]

Answer:

8.2 units

Step-by-step explanation:

Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC

Recall the Law of Cosines

$a^2=b^2+c^2-2bc\cdot cos(A)$

Identify angles and sides

$m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6$

Solve for side "a"

$a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2$

Therefore, the length of line segment BC is about 8.2 units

8 0

2 years ago

2,17,82,257,626,1297 next one please ?

In-s [12.5K]

The easy thing to do is notice that 1^4 = 1, 2^4 = 16, 3^4 = 81, and so on, so the sequence follows the rule $n^4+1$ . The next number would then be fourth power of 7 plus 1, or 2402.

And the harder way: Denote the n-th term in this sequence by $a_n$ , and denote the given sequence by $\{a_n\}_{n\ge1}$ .

Let $b_n$ denote the n-th term in the sequence of forward differences of $\{a_n\}$ , defined by

$b_n=a_{n+1}-a_n$

for n ≥ 1. That is, $\{b_n\}$ is the sequence with

$b_1=a_2-a_1=17-2=15$

$b_2=a_3-a_2=82-17=65$

$b_3=a_4-a_3=175$

$b_4=a_5-a_4=369$

$b_5=a_6-a_5=671$

and so on.

Next, let $c_n$ denote the n-th term of the differences of $\{b_n\}$ , i.e. for n ≥ 1,

$c_n=b_{n+1}-b_n$

so that

$c_1=b_2-b_1=65-15=50$

$c_2=110$

$c_3=194$

$c_4=302$

etc.

Again: let $d_n$ denote the n-th difference of $\{c_n\}$ :

$d_n=c_{n+1}-c_n$

$d_1=c_2-c_1=60$

$d_2=84$

$d_3=108$

etc.

One more time: let $e_n$ denote the n-th difference of $\{d_n\}$ :

$e_n=d_{n+1}-d_n$

$e_1=d_2-d_1=24$

$e_2=24$

etc.

The fact that these last differences are constant is a good sign that $e_n=24$ for all n ≥ 1. Assuming this, we would see that $\{d_n\}$ is an arithmetic sequence given recursively by

$\begin{cases}d_1=60\\d_{n+1}=d_n+24&\text{for }n>1\end{cases}$

and we can easily find the explicit rule:

$d_2=d_1+24$

$d_3=d_2+24=d_1+24\cdot2$

$d_4=d_3+24=d_1+24\cdot3$

and so on, up to

$d_n=d_1+24(n-1)$

$d_n=24n+36$

Use the same strategy to find a closed form for $\{c_n\}$ , then for $\{b_n\}$ , and finally $\{a_n\}$ .

$\begin{cases}c_1=50\\c_{n+1}=c_n+24n+36&\text{for }n>1\end{cases}$

$c_2=c_1+24\cdot1+36$

$c_3=c_2+24\cdot2+36=c_1+24(1+2)+36\cdot2$

$c_4=c_3+24\cdot3+36=c_1+24(1+2+3)+36\cdot3$

and so on, up to

$c_n=c_1+24(1+2+3+\cdots+(n-1))+36(n-1)$

Recall the formula for the sum of consecutive integers:

$1+2+3+\cdots+n=\displaystyle\sum_{k=1}^nk=\frac{n(n+1)}2$

$\implies c_n=c_1+\dfrac{24(n-1)n}2+36(n-1)$

$\implies c_n=12n^2+24n+14$

$\begin{cases}b_1=15\\b_{n+1}=b_n+12n^2+24n+14&\text{for }n>1\end{cases}$

$b_2=b_1+12\cdot1^2+24\cdot1+14$

$b_3=b_2+12\cdot2^2+24\cdot2+14=b_1+12(1^2+2^2)+24(1+2)+14\cdot2$

$b_4=b_3+12\cdot3^2+24\cdot3+14=b_1+12(1^2+2^2+3^2)+24(1+2+3)+14\cdot3$

and so on, up to

$b_n=b_1+12(1^2+2^2+3^2+\cdots+(n-1)^2)+24(1+2+3+\cdots+(n-1))+14(n-1)$

Recall the formula for the sum of squares of consecutive integers:

$1^2+2^2+3^2+\cdots+n^2=\displaystyle\sum_{k=1}^nk^2=\frac{n(n+1)(2n+1)}6$

$\implies b_n=15+\dfrac{12(n-1)n(2(n-1)+1)}6+\dfrac{24(n-1)n}2+14(n-1)$

$\implies b_n=4n^3+6n^2+4n+1$

$\begin{cases}a_1=2\\a_{n+1}=a_n+4n^3+6n^2+4n+1&\text{for }n>1\end{cases}$

$a_2=a_1+4\cdot1^3+6\cdot1^2+4\cdot1+1$

$a_3=a_2+4(1^3+2^3)+6(1^2+2^2)+4(1+2)+1\cdot2$

$a_4=a_3+4(1^3+2^3+3^3)+6(1^2+2^2+3^2)+4(1+2+3)+1\cdot3$

$\implies a_n=a_1+4\displaystyle\sum_{k=1}^3k^3+6\sum_{k=1}^3k^2+4\sum_{k=1}^3k+\sum_{k=1}^{n-1}1$

$\displaystyle\sum_{k=1}^nk^3=\frac{n^2(n+1)^2}4$

$\implies a_n=2+\dfrac{4(n-1)^2n^2}4+\dfrac{6(n-1)n(2n)}6+\dfrac{4(n-1)n}2+(n-1)$

$\implies a_n=n^4+1$

4 0

3 years ago

The values in the table represent a linear function. How does the value of y change in relation to a change in the value of x?

Verizon [17]

if x is changed by 2 , the y changes by +3, Option B is the correct answer.

<h3>What is the equation of a Linear Function ?</h3>

The equation of a Linear Function is given by

y = mx +c

here m is the slope , c is the intercept on the y axis

The data is given in the table

To determine the relation , a function needs to be established between the variables.

m = ( y2 -y1 )/(x2-x1)

m = (-7 +10) /(-2+4)

m = 3 / 2

y = (3/2)x + c

at x = 0 , y= -4

-4 = 0 + c

c = -4

The function is

y = (3/2) x - 4

if x is changed by 2 , the y changes by +3

Therefore Option B is the correct answer.

To know more about Linear Function

brainly.com/question/21107621

#SPJ1

7 0

2 years ago

Find the unknown measures of the indicated angles.

Sever21 [200]

The angles of a triangle always equal to 180 degrees.

Knowing this, you can solve this by this equation

Angle A + Angle B + Angle C = 180

43 + 85 + Angle C = 180

Angle C = 180 - 43 - 85
Angle C = 52

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3 years ago

Do Dilation's always increase the length of line segments?

lyudmila [28]

Answer:

true

Step-by-step explanation:

I'm pretty sure it's trur

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3 years ago