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Arlecino [84]
2 years ago
8

Find the median of the following set of data: 52,84,94,102,94,89,73

Mathematics
1 answer:
nydimaria [60]2 years ago
8 0

Answer:

Step-by-step explanation:

the median is 89, the mode is 94, and the mean is 84

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Use the Parent function and Function 2 to choose the best statement comparing the graphs to each other.
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the 7th grade teachers want to buy the principal a giant stuffed tiger for his office costing 50.00. however, the store is havei
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The mean of five numbers is 8. when another number is added the mean is 7. find the number added
sasho [114]

Answer:

\large \boxed{\sf \ \ 2  \ \ }

Step-by-step explanation:

Hello,

<u>The mean of five numbers is 8</u> so we can write

\dfrac{x_1+x_2+x_3+x_4+x_5}{5}=8

<u>When another number is added the mean is 7</u>, let s note x the another number we can write

\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7

From the first equation we can say

x_1+x_2+x_3+x_4+x_5=8*5=40

So the second equation becomes

\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7\\\\ \dfrac{40+x}{6}=7\\\\40 + x = 6*7=42\\\\ x = 42-40 = 2\\

The solution is then 2

Hope this helps

4 0
3 years ago
Barron's reported that the average number of weeks an individual is unemployed is 17.5 weeks. Assume that for the population of
Olin [163]

Answer:

P(16.5

And using the normal standard table or excel we find the probability:

P(-1.768< Z< 1.768) = P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the avergae number of weeks an individual is unemployed of a population, and for this case we know the distribution for X is given by:

X \sim N(17.5,4)  

Where \mu=17.5 and \sigma=4

Since the distribution for X is normal then, the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu= 17.5, \frac{\sigma}{\sqrt{n}}= \frac{4}{\sqrt{50}}=0.566)

We select a sample of n =50 people. And we want to find the following probability

P(16.5

And using the normal standard table or excel we find the probability:

P(-1.768< Z< 1.768) = P(Z

4 0
3 years ago
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