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Arlecino [84]
3 years ago
8

Find the median of the following set of data: 52,84,94,102,94,89,73

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Answer:

Step-by-step explanation:

the median is 89, the mode is 94, and the mean is 84

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Penelope earned $50 in May. She earned $60 in June.
laila [671]

Answer:

20% Increase

Step-by-step explanation:

Percentages can be put vice versa. So 20% Of 50 = 50% Of 20 Which Equals 10.

Mark me as brainliest please

3 0
3 years ago
Sue invests £9000 in an account for one year.
Anika [276]

Answer:

£151.20

Step-by-step explanation:

20%= 100%divided by 5

To find 100% from 20% you x by 5

so you times 30.24 by 5

30.24x 5 = 151.2

So the answer is £151.20

interest percentage rate would be 1.6754%

3 0
3 years ago
2. Is 4x – 3 = 19 true, false, or open? <br> A)true<br> B)false<br> C)open
ElenaW [278]

Answer: B. False

Step-by-step explanation: Because you do

4x - 3 = 19

+3 +3 =4x = 22

You divide 4x divide by 4 and you get x

Then you divide 22 by 4 and get 5.5

So the answer is X = 5.5

6 0
3 years ago
Solve the equation for x.<br> 27(x - 108) = 54
Sidana [21]
X = 110

110-108 = 2

27*2=54
4 0
3 years ago
Read 2 more answers
A researcher determines that students are active about 60 + 12 (M + SD) minutes per day. Assuming these data are normally distri
rjkz [21]

Answer:

The correct option is (b).

Step-by-step explanation:

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

The mean and standard deviation of the active minutes of students is:

<em>μ</em> = 60 minutes

<em>σ </em> = 12 minutes

Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.

The correct option is (b).

4 0
3 years ago
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