Question

Xalign="absmiddle" class="latex-formula">

Answer 1

Answer:

$x = 3\ or\ x = 7$

Step-by-step explanation:

Given

$x^{2}-8x+14=2x-7$

Required

Solve

Equate to 0

$x^{2}-8x-2x+14+7=0$

$x^{2}-10x+21=0$

Expand

$x^{2}-7x-3x+21=0$

Factorize

$x(x-7)-3(x-7)=0$

Factor out x - 7

$(x-3)(x-7)=0$

Split

$x - 3 = 0\ \ x - 7 = 0$

Solve

$x = 3\ or\ x = 7$