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Tom [10]
3 years ago
9

Recently, frogs have been disappearing from the wild due to a contagious fungus. To monitor the current population in a certain

region, Emma collects 60 frogs, marks them, and releases them. Later, she collects 300 frogs and finds that 18 of them are marked.
What is the best estimate for the frog population?
Mathematics
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

prob. around 5,000 frogs are left in the world

Step-by-step explanation:

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The depreciating value of a semi-truck can be modeled by y = Ao(0.83)x, where y is the remaining value of the semi, x is the tim
xenn [34]
The exponential graph is shown below.

The initial value when the time is zero is 70000. An initial value is normally shown as the point where the graph crosses the y-axis.

If the initial value was to be 50000, the curve would have crossed the y-axis at 50000

The correct answer is the first statement

6 0
4 years ago
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What is the value of w?<br><br><br> A.) 7<br> B.) 3.5<br> C.) 7 square root of 3<br> D.) 14
sammy [17]
D. 14 

LL = 1/2 * Hsqrt3
7sqrt3 = 1/2 * ysqrt3
24.25 = ysqrt3
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4 0
4 years ago
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Dina planted a six-foot tree in her backyard which she expects to grow at the rate of 4 feet per year. Find the equation of the
Scrat [10]

Answer:

y = 6 + 4x

After 4 years, the tree would be 22 ft tall.

Step-by-step explanation:

Hi there!

Let x = the number of years that pass

Let y = the height of the tree (ft)

We're given that the 6-foot tree grows at a rate of 4 ft per year. This means that the height of the tree will be equal to 6 ft, the original height, plus another 4 ft every year that passes.

Height of tree = 6 feet + 4 feet × number of years that pass

y = 6 + 4x

To solve for how tall the tree would be 4 years after Dina plants it, replace x with 4, since 4 years have passed:

y = 6 + 4(4)

y = 6 + 16

y = 22

Therefore, the tree would be 22 ft tall.

I hope this helps!

8 0
3 years ago
Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe
Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798

The probability is 0.5798 or 57.98%.

8 0
3 years ago
Please help. Due soon.
Orlov [11]
The function represents exponential growth (since the exponent is positive).

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4 0
3 years ago
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