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MA_775_DIABLO [31]
3 years ago
10

Is this right??? Yes or no

Mathematics
1 answer:
anastassius [24]3 years ago
4 0

Your answer is incorrect, the correct answer is "variance of sample means"

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To get started, we will use the general formula for bacteria growth/decay problems:

A_{f} =  A_{i} ( e^{kt} )

where: 
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time


For doubling problems, the general formula can be shortened to:

kt = ln(2)

Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:

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k_{1} = ln(2)/t
k_{1} = ln(2)/2 = 0.34657 per hour

Jaquan (2):
k_{2} = ln(2)/t
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Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).

Note: All units must be constant, so convert day to hours.

A_{f1} = 50( e^{0.34657(24)})
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Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:

A_{f2} = 204,800 =  A_{i2} ( e^{0.23105(24)} )
A_{i2} = 800

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3 years ago
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