Answer:
the g force from when it was thrown to were it comes back down
Explanation:
while your throwing it you applying force which it would have a stronger g force but when the gravitationally pull come into effect it's will lose some of that force
Answer:
Elastic potential energy into kinetic energy
Explanation:
Initially the energy is stored inside the spring, which is compressed. This form of energy is called elastic potential energy, and its formula is
![U=\frac{1}{2}kx^2](https://tex.z-dn.net/?f=U%3D%5Cfrac%7B1%7D%7B2%7Dkx%5E2)
where k is the spring constant, which gives the 'strength' of the spring, while x is the compression/stretching of the spring with respect to its equilibrium position.
When the spring unwinds, it returns to its equilibrium position, so x becomes zero and the potential energy converts into another form of energy, which is related to the motion of the car (in fact, the car starts moving). This form of energy is called kinetic energy, and its formula is
![K=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
where m is the mass of the car and v is its speed.
Thanks for points...
But can you type this question.. As it becomes hard to answer if it's in the picture..
Answer:
2.3×10−1
Explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
Answer:
<h2>42.67N</h2>
Explanation:
Step one:
<u>Given </u>
mass m= 0.32kg
intital velocity, u= 14m/s
final velocity v= 22m/s
time= 0.06s
Step two:
<u>Required</u>
Force F
the expression for the force is
F=mΔv/t
F=0.32*(22-14)/0.06
F=(0.32*8)/0.06
F=2.56/0.06
F=42.67N
The average force exerted on the bat 42.67N