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Elanso [62]
3 years ago
5

If someone were to throw an object vertically, and catch it as it returned back down, describe how the velocity vector of this o

bject changes over this period.
Physics
1 answer:
VMariaS [17]3 years ago
3 0

Answer:

the g force from when it was thrown to were it comes back down

Explanation:

while your throwing it you applying force which it would have a stronger g force but when the gravitationally pull come into effect it's will lose some of that force

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An unknown material, m1 = 0.45 kg, at a temperature of T1 = 91 degrees C is added to a Dewer (an insulated container) which cont
goldenfox [79]

Answer:

Explanation:

Let the specific heat of material be s

heat lost by material = m₁ s (T 1 - T ) ,  (T 1 - T ) is fall in temp , m₁ is mass of material

= .45 x s x (91 - 31.4 )

= 26.82 s

Heat gained by water

= m₂ cw (T2 - T )

1.3 x 4186 x ( 31.4 - 23 )

heat lost = heat gained

m₂ cw (T2 - T ) = m₁ s (T 1 - T )

1.3 x 4186 x ( 31.4 - 23 ) =  .45 x s x (91 - 31.4 )

45711.12 = 26.82 s

s = 1704.36

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4 years ago
Which one is an example of kinetic energy
aleksley [76]
The correct answer is A:) hope it helps :0
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4 years ago
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Funding has little influence on the number of researchers working on a given project.
tatiyna
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The most accurate statement is B.

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3 years ago
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Which of the following is not a measurement taken by a radiosonde?
MariettaO [177]

Correct answer choice is :


A) Atmospheric composition


Explanation:


A radiosonde is a battery-powered telemetry device transmitted into the environment normally by a weather balloon that regulates several atmospheric parameters and sends them by radio to a ground receiver. The radiosonde is a small, expandable device unit that is recessed below a six-foot-wide balloon inflated with hydrogen or helium. As the radiosonde stands at about 1,000 feet/minute, sensors on the radiosonde measure forms of pressure, temperature, and related moisture.

5 0
3 years ago
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as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p
miv72 [106K]

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

E = (3)(230\ m/s)(0.61\ T)Sin90^o

<u>E = 420.9 N/C</u>

3 0
3 years ago
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