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3 years ago

15

Aml needs to divide these base ten blocks into 4 equal groups, 11 Describe a model that would show how many are in each group. T

he model will contain ten and ones in each group. pls help im crying

1 answer:

Svetllana [295]3 years ago

7 0

Answer:

<h3>The model will contain 19 ten and 4</h3>

Step-by-step explanation:

11 ÷ 4 = 2 + 2 = 4

1 + 4 + 4 = 9

19 ÷ 4 = 4

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Solve <br> (6x + 5) - (x + 3)

Pie

Answer:

5x+2

Step-by-step explanation:

6x-x=5x and 5-3=2

so 5x+2 is the answer.

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3 years ago

Yeyey! Happy Friday!!!<br> Help please I'll give brainliest '^'

seropon [69]

Answer:

75%

Step-by-step explanation:

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3 years ago

Read 2 more answers

It takes 0.5 gallon of cream to make 1 pound of butter.

worty [1.4K]

Answer:

0.5 pounds of butter.

Explanation

X pounds for 0.25 gallons.

0.5 gallon of cream - 1 pound of butter

0.25 gallons of cream - X pounds of butter

Applying cross multiplication:

0.5X = 0.25

X = 0.25 over 0.5 or 0.25/0.5

X = 0.5

Therefor, you could make 0.5 pounds of butter with 0.25 gallons of cream.

7 0

3 years ago

A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc

Nutka1998 [239]

a. At its maximum height, the ball has zero vertical velocity, so

$-\left(28\dfrac{\rm m}{\rm s}\right)^2=2(-g)(y_{\rm max}-17\,\mathrm m)$

$\implies y_{\rm max}=57\,\mathrm m$

b. The ball's height in the air $y$ at time $t$ is given according to

$y=17\,\mathrm m+\left(28\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2$

Solve for $t$ when $y=0$ :

$17+28t-4.9t^2=0\implies t\approx6.3\,\mathrm s$

3 0

3 years ago

12. Using the value of 0.538 for the proportion of those surveyed who said they exercise at least 30 minutes three or more days

ICE Princess25 [194]

Answer:

$ME=1.96\sqrt{\frac{0.538 (1-0.538)}{15235}}=0.00792$

The margin of error on this case is approximated $\pm 0.792\%$ who is very clos to the +1% reported by the Gallup.

Step-by-step explanation:

Assuming this previous info : "Results are based on telephone interview conducted as part of the Gallup-Healthways Well-Being Index survey June 1–30,2013, with a random sample of 15,235 adults, aged 18 and older, living in all 50 U.S. states and the District of Columbia.

For results based on the total sample of national adults, one can say with 95% confidence that the maximum margin of sampling error is ±1 percentage point."

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The estimated proportion on this case is $\hat p =0.538$ and n =15235, the margin of error is given by:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And if we replace we got:

$ME=1.96\sqrt{\frac{0.538 (1-0.538)}{15235}}=0.00792$

The margin of error on this case is approximated $\pm 0.792\%$ who is very clos to the +1% reported by the Gallup.

5 0

3 years ago