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BartSMP [9]
3 years ago
8

an author write 6 pages in one hour how many pages will she write in 5 hours. PLS DO IT STEP BY STEP​

Mathematics
2 answers:
faltersainse [42]3 years ago
7 0

Answer:

30 pages

Step-by-step explanation:

This can be written as an simple ratio (x/y), a ratio of 6/1

X= is the number of pages

Y= the hour(s)

He can write 6 pages in 1 hour, now we have to find how many pages he can write in 5 hours

This can be write this as an equation, we already have the first ratio and we know the Y value of the second ratio which is 5

6/1= x/5

To find X or how many pages he can write in 5 hours, you have to cross multiply and you will get

30=1x or x=30

So he can write 30 pages in 5 hours

dusya [7]3 years ago
6 0

\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}

1 hour = 6 pages

So,

5 hours = 6×5

ㅤㅤㅤㅤ= 30 pages

therefore, She writes 30 pages in 5 hours.

  • Thanks.
  • Hope it helps.
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The number of wrecks at a certain intersection varies directly as the number of cars that travel through the intersection. If th
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The number of cars that have passed through the intersection is 245.

<h3>How many cars passed through the intersection?</h3>

Direct variation is when two variables move in the same direction. If one variable increases, the other variable increases.

The equation that represents direct variation is; c = wk

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3 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

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As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

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t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

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When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

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