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3 years ago

Find the area of a triangle with the following measures: B-12 inches H-5 inches

1 answer:

3 0

The area would 30 in^2
Reason:
Area of a triangle =1/2 bh
Area= 1/2 (12)(5)
Area =(6)(5) (because a half times 12 =6)
Therefore Area =30 in^2
Hopefully that helps, if not I apologize

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These expressions below represent four numbers. The value of the median of these expressions is 12.

Airida [17]

Answer:

The mean is 15

Explanation:

The x value that would get a median of 12 is three, which when taken the mean of the numbers when x is three, you get 15

6 0

3 years ago

You are planning a road trip and there are 15 different cities you would like to visit. Due to time constraints, you can only vi

kumpel [21]

Answer: 32760 ways.

Step-by-step explanation:

To solve this, we first determine the number of ways to select 4 countries from 15, we calculate number of ways to visit these 4 places then we multiply.

Selecting number of ways to choose 4 cities from 15 is by using the combination formula, which becomes 15C4

Number of ways to visit these 4 cities = 4!

Hence,total number of ways of visiting these 4 cities = 15C4 * 4! = 32760ways

3 0

3 years ago

Consider the function f(x)=9-x^2/x^2-4 For which intervals is f(x) positive? Check ALL that apply.

solong [7]

Answer:

a. f (x) < 0 for x ∈ (-∞ ,-3)

b. f (x) > 0 for x ∈ (-3,-2)

c. f (x) < 0 for x ∈ (-2,2)

d. f (x) > 0 for x ∈ (2,3)

e.f (x) < 0 for x ∈ (3,∞)

Step-by-step explanation:

Here, the given function is: $f(x)= \frac{9-x^2}{x^2-4}$

Now, to check for the sign of f(x) at x = k, put the value of x from the given interval.

We get:

<u>a. (-infinity, -3) </u>

put k = -4 from the given interval

We get $f(-4)= \frac{9-(-4)^2}{(-4)^2-4} = \frac{9-16}{16-4} = \frac{-7}{12}$

⇒ f (x) < 0 for x ∈ (-∞ ,-3)

b. (-3, -2)

put k = -2.5 from the given interval

We get $f(-2.5)= \frac{9-(-2.5)^2}{(-2.5)^2-4} = \frac{9-6.25}{6.25-4} = \frac{2.75}{2.25} > 0$

⇒ f (x) > 0 for x ∈ (-3,-2)

c. (-2, 2)

put k = 0 from the given interval

We get $f(0)= \frac{9-(0)^2}{(0)^2-4} = \frac{9}{-4} = -\frac{9}{4} < 0$

⇒ f (x) < 0 for x ∈ (-2,2)

d. (2, 3)

put k =2.5 from the given interval

We get $f(2.5)= \frac{9-(2.5)^2}{(2.5)^2-4} = \frac{9-6.25}{6.25-4} = \frac{2.75}{2.25} > 0$

⇒ f (x) > 0 for x ∈ (2,3)

e. (infinity, 3)

put k = 4 from the given interval

We get $f(4)= \frac{9-(4)^2}{(4)^2-4} = \frac{9-16}{16-4} = \frac{-7}{12}$

⇒ f (x) < 0 for x ∈ (3,∞)

7 0

3 years ago

solve the inequality below. Use the drop-down menus to describe the solution and its graph -7x+13>41

3241004551 [841]

｡☆✼★ ━━━━━━━━━━━━━━ ☾

-7x + 13 > 41

- 13

-7x > 28

/ -7

x < -4

Have A Nice Day ❤

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7 0

4 years ago

How do you seqence numbers like 1,5,25,125

miskamm [114]

1, 5, 25, 125 is the correct way to sequence these numbers

5 0

4 years ago

Read 2 more answers