All categories

3 years ago

Find the area of a triangle with the following measures: B-12 inches H-5 inches

1 answer:

3 0

The area would 30 in^2
Reason:
Area of a triangle =1/2 bh
Area= 1/2 (12)(5)
Area =(6)(5) (because a half times 12 =6)
Therefore Area =30 in^2
Hopefully that helps, if not I apologize

You might be interested in

Solve this equation: -7x + 12 – 2x = 23 + 13.0

LiRa [457]

Answer:

Step-by-step explanation:

We can combine the -7x and the -2x and the left side to get -9x and the 23 and 13 on the right side to get 36.

This gives us

-9x + 12 = 36

Subtacting 12 from both sides gives us

-9x = 24

dividing by -9 gives us

x = - 8/3

5 0

3 years ago

Read 2 more answers

1. Select all values of x that are solutions to the equation: -2(x + 4)(3x - 18) = 0A) -6B) -4C) -2D) OE) 2F) 4G) 6

navik [9.2K]

$\begin{gathered} -2(x+4)(3x-18)=0 \\ \text{There are two factors here which are} \\ -2(x+4)\text{ and} \\ (3x-18) \\ \text{This means, either} \\ 2(x+4)=0 \\ 2x+8=0 \\ 2x=-8 \\ \text{Divide both sides by 2} \\ x=-4 \\ OR \\ 3x-18=0 \\ 3x=18 \\ \text{Divide both sides by 3} \\ x=6 \\ \text{Therefore,} \\ x=-4\text{ or} \\ x=6 \end{gathered}$

x = -4 OR x = 6

The correct options are B and G

6 0

1 year ago

Write an equation for the line in slope-intercept form.

atroni [7]

Answer:

y=3x+5

Step-by-step explanation:

Slope is rise/run. To find it, you first see how many units it goes up, followed by how many units it goes to the right. If you look at the point (-1, 2), it rises 3 tiles, and runs 1 tile until it hits the next whole number. Because your little formula is rise/run, it would be 3/1, or 3. And to get your y-intercept, it's just when it intersects the y-axis, which is at 5. So, your equation would be y=3x+5

3 0

3 years ago

Solve the following sysyem of equations by the substitution method. 5x+y=8<br> 3×+y=8

meriva

$5x+y=8\\
3x+y=8\\\\
y=-5x+8\\
3x+y=8\\\\
3x-5x+8=8\\
-2x=0\\
x=0\\\\
y=-5\cdot0+8\\
y=8\\\\
\boxed{(x,y)=(0,8)}$

6 0

3 years ago

Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

3 years ago

Read 2 more answers