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2 years ago

PLEASE HELP QUICK!!!

Mathematics

2 answers:

Masja [62]2 years ago

8 0

Answer:

Step-by-step explanation:

Artemon [7]2 years ago

4 0

Answer:

Step-by-step explanation:

lines are parallel so 180 - 125 = 55 and angle m is a verical angle to it to they are the same so m = 55 degrees

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Whats the area of a circle with a circumference of 31.4unit

marin [14]

Answer:

78.54

Step-by-step explanation:

first you have to divided 31.4 by 3.14 to get your diameter so you can get your radius. 31.4 divided by 3.14 equals 10 and 10 divided by 2 equals 5 which is you radius. The formula for area for a circle is πr². 5 squared is 25 and 3.14 times 25 equals 78 .54 which is your answer.

8 1

3 years ago

Simplify the square root of 27 over 12

Hunter-Best [27]

$\sqrt{ \frac{27}{12} }$

${ \frac{ \sqrt{27} {} }{ \sqrt{12}}$

$\frac{ \sqrt{9 * 3} }{ \sqrt{4 * 3} }$

$\frac{ \sqrt{9} \sqrt{3} }{ \sqrt{4} \sqrt{3} }$

$\frac{3 \sqrt{3} }{2 \sqrt{3} }$

$\frac{3}{2}$

$1 \frac{1}{2}$

5 0

3 years ago

Triple the difference of 6 less than a number

Allisa [31]

Answer:

3(x-6)

Step-by-step explanation:

6 0

3 years ago

A survey of middle school students asked: What is your favorite winter sport? The results are summarized below:Favorite Winter S

Annette [7]

Answer:

a) 31.38%

b) 28.44%

c) 33.33%

d) 73.46%

e) 53.89%

Step-by-step explanation:

<h3>(See picture attached for sub-totals) </h3>

a) What is the probability of selecting a student whose favorite sport is skiing?

P = 171/545 = 0.3138 = 31.38%

b) What is the probability of selecting a 6th grade student?

P = 155/545 = 0.2844 = 28.44%

c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?

P = 70/210 = 0.3333 = 33.33%

d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?

P = 155/211 = 0.7346 = 73.46%

e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?

P = 180/(171+163) = 180/334 = 0.5389 = 53.89%

7 0

3 years ago

If (x^2 - 1) is a factor of ax^4 + bx^3 + cx^2 + dx + e, show that a + c + e = b + d = 0

alisha [4.7K]

$x^2-1=x^2-1^2=(x-1)(x+1)$

If x²-1 is a factor of the polynomial, both x-1 and x+1 are factors of it.

According to the remainder theorem, if a binomial x-a is a factor of a polynomial p(x), then p(a)=0.

If x-1 and x+1 are factors of the polynomial p(x)=ax⁴+bx³+cx²+dx+e, then p(1)=0 and p(-1)=0.

$p(1)=a \times 1^4+b \times 1^3 + c \times 1^2+ d \times 1+e \\
p(-1)=a \times (-1)^4 + b \times (-1)^3 + c \times (-1)^2 + d \times (-1)+e \\ \\
p(1)=a+b+c+d+e \\
p(-1)=a-b+c-d+e \\ \\
p(1)=0 \\
p(-1)=0 \\ \\ \hbox{add both equations:} \\
a+b+c+d+e=0 \\
\underline{a-b+c-d+e=0} \\
2a+2c+2e=0 \\
2(a+c+e)=0 \\
a+c+e=0 \\ \\
\hbox{substitute 0 for a+c+e in the first equation:} \\
a+b+c+d+e=0 \\
(a+c+e)+b+d=0 \\
0+b+d=0 \\
b+d=0 \\ \\
\boxed{a+c+e=b+d=0} \\
\hbox{proved } \checkmark$

8 0

3 years ago