1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Blizzard [7]
3 years ago
11

Rate this song

Mathematics
1 answer:
Alex17521 [72]3 years ago
3 0

Answer:

100/100

Step-by-step explanation:

You might be interested in
Find the median of the data.
kipiarov [429]

Answer:

  • 92.5

Step-by-step explanation:

<u>The data given:</u>

  • 93, 81, 94, 71, 89, 92, 94, 99

<u>Put the data in the ascending order:</u>

  • 71, 81, 89, 92, 93, 94, 94, 99

<u>Since the data size is even, the median is the average of middle two:</u>

  • median = (92 + 93)/2 = 92.5

4 0
2 years ago
A)A cuboid with a square x cm and height 2xcm². Given total surface area of the cuboid is 129.6cm² and x increased at 0.01cms-¹.
Nutka1998 [239]

Answer: (given assumed typo corrections)


(V ∘ X)'(t) = 0.06(0.01t+3.6)^2 cm^3/sec.


The rate of change of the volume of the cuboid in change of volume per change in seconds, after t seconds. Not a constant, for good reason.



Part B) y'(x+Δx/2)×Δx gives exactly the same as y(x+Δx)-y(x), 0.3808, since y is quadratic in x so y' is linear in x.


Step-by-step explanation:

This problem has typos. Assuming:

Cuboid has square [base with side] X cm and height 2X cm [not cm^2]. Total surface area of cuboid is 129.6 cm^2, and X [is] increas[ing] at rate 0.01 cm/sec.


129.6 cm^2 = 2(base cm^2) + 4(side cm^2)

= 2(X cm)^2 + 4(X cm)(2X cm)

= (2X^2 + 8X^2)cm^2

= 10X^2 cm^2

X^2 cm^2 = 129.6/10 = 12.96 cm^2

X cm = √12.96 cm = 3.6 cm


so X(t) = (0.01cm/sec)(t sec) + 3.6 cm, or, omitting units,

X(t) = 0.01t + 3.6

= the length parameter after t seconds, in cm.


V(X) = 2X^3 cm^3

= the volume when the length parameter is X.


dV(X(t))/dt = (dV(X)/dX)(X(t)) × dX(t)/dt

that is, (V ∘ X)'(t) = V'(X(t)) × X'(t) chain rule


V'(X) = 6X^2 cm^3/cm

= the rate of change of volume per change in length parameter when the length parameter is X, units cm^3/cm. Not a constant (why?).


X'(t) = 0.01 cm/sec

= the rate of change of length parameter per change in time parameter, after t seconds, units cm/sec.

V(X(t)) = (V ∘ X)(t) = 2(0.01t+3.6)^3 cm^3

= the volume after t seconds, in cm^3

V'(X(t)) = 6(0.01t+3.6)^2 cm^2

= the rate of change of volume per change in length parameter, after t seconds, in units cm^3/cm.

(V ∘ X)'(t) = ( 6(0.01t+3.6)^2 cm^3/cm )(0.01 cm/sec) = 0.06(0.01t+3.6)^2 cm^3/sec

= the rate of change of the volume per change in time, in cm^3/sec, after t seconds.


Problem to ponder: why is (V ∘ X)'(t) not a constant? Does the change in volume of a cube per change in side length depend on the side length?


Question part b)


Given y=2x²+3x, use differentiation to find small change in y when x increased from 4 to 4.02.


This is a little ambiguous, but "use differentiation" suggests that we want y'(4.02) yunit per xunit, rather than Δy/Δx = (y(4.02)-y(4))/(0.02).


Neither of those make much sense, so I think we are to estimate Δy given x and Δx, without evaluating y(x) at all.

Then we want y'(x+Δx/2)×Δx


y(x) = 2x^2 + 3x

y'(x) = 4x + 3


y(4) = 44

y(4.02) = 44.3808

Δy = 0.3808

Δy/Δx = (0.3808)/(0.02) = 19.04


y'(4) = 19

y'(4.01) = 19.04

y'(4.02) = 19.08


Estimate Δy = (y(x+Δx)-y(x)/Δx without evaluating y() at all, using only y'(x), given x = 4, Δx = 0.02.


y'(x+Δx/2)×Δx = y'(4.01)×0.02 = 19.04×0.02 = 0.3808.


In this case, where y is quadratic in x, this method gives Δy exactly.

6 0
3 years ago
What was edwin average rate of jogging in miles per hour​
Svetach [21]

Answer:Edwin average rate of jogging in miles per hour is

2 miles per hour

At the end of 30 min Edwin completed the track 3 times before Jose.

Step-by-step explanation:

Hope this helps

6 0
3 years ago
PLEASE I NEED HELPP
LiRa [457]

48^2+14^2=x^2\\x^2=2500\\x=50

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B3%7D%2B4%5Cright%29%5Cleft%281%2B%5Csqrt%7B3%7D%5Cright%29" id="TexFormula
kirza4 [7]

Answer:

\huge\boxed{\sf 7 + 5\sqrt{3} }

Step-by-step explanation:

(\sqrt{3} +4)(1+\sqrt{3})\\\\= \sqrt{3}(1+\sqrt{3} )+4(1+\sqrt{3})\\\\= \sqrt{3} + (\sqrt{3} )^2 + 4 + 4\sqrt{3} \\\\= \sqrt{3} + 3+4+4\sqrt{3}  \\\\= 7 + \sqrt{3}  + 4\sqrt{3} \\\\Take \ \sqrt{3} \ common\\\\= 7 + \sqrt{3} (1+4)\\\\= 7 + \sqrt{3}(5)\\\\= 7 + 5\sqrt{3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
2 years ago
Other questions:
  • Need help on how to do this please thanks
    13·1 answer
  • How do you solve y=4/5x+5
    9·1 answer
  • Sarah has a 6 cup bag of rice. If a serving is ¾ of a cup, how many servings does Sarah have?
    8·2 answers
  • What is 619 divided by 7
    7·1 answer
  • Write the equation that describes that function. Express slope intercept form. IM BEGGING FOR HELP PLEASE
    6·1 answer
  • 70. Dominic buys a new suit that is on sale for 20% off
    15·1 answer
  • i need help please i have alot of problems on math and i was hoping you all can help me and explain it to me
    5·1 answer
  • Plz help! I will do anything
    9·1 answer
  • Find the value of x and y in the parallelogram ​
    5·1 answer
  • Put all the order possibilities for these.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!