The answer is potential for this question
Answer:
work done is 470400 J
Explanation:
given data
long = 3 m
wide = 2 m
deep = 4 m
density = 1000 kg/m³
to find out
Find the amount of work in joules
solution
we know here volume = area × length
so
area = 0.5 ×base×height
area = 0.5 ×2×4
area = 4 m²
so volume = 4 × 3 = 12 m³
and
weight of water = volume ×density×g
weight = 12 × 1000 × 9.8
weight = 117600 N
so
work done = weight × height
work done = 117600× 4
work done = 470400 J
