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MAVERICK [17]
3 years ago
13

If a cart of 2 kg mass has a force of 8 newtons exerted on it, what is its acceleration?

Physics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0
Force = mass * acceleration

F = ma

8 N =  2 kg * a

8 = 2a

2a = 8

a = 8/2 = 4

acceleration = 4 m/s²
DaniilM [7]3 years ago
7 0

Answer:

4m/s^2

Explanation:

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ddd [48]

Answer:

a) 30.82 m/s

b)  183.33 Hz

Explanation:

a)

V = speed of the sound = 339 m/s

v = speed of the train = ?

f' = observed frequency by the observer = 220 Hz

f = actual frequency of the observer = 200 Hz

using the equation

f' = \frac{fV}{V - v}

220 = \frac{(200)(339)}{339 - v}

v =  30.82 m/s

b)

V = speed of the sound = 339 m/s

v = speed of the train = 30.82 m/s

f'' = observed frequency by the observer as train moves away = ?

f = actual frequency of the observer = 200 Hz

using the equation

f'' = \frac{fV}{V + v}

f'' = \frac{(200)(339)}{339 + 30.82}

f'' = 183.33 Hz

3 0
3 years ago
If an amount of heat Q is needed to increase the temperature of a solid metal sphere of diameter D from 4°C to 7°C, the amount o
Hitman42 [59]

Answer:

Q = c M ΔT      where c is the heat capacity and M the mass present

Q2 / Q1 = M2 / M1    since the other factors are the same

M = ρ V     where ρ is the density

M = ρ Π (d / 2)^2           where d is the diameter of the sphere

M2 / M1 = (2 D/2)^2 / (D/2)^2 = 4

It will take 4Q heat to heat the second sphere

7 0
2 years ago
ASAP TWENTY POINTS What type of image is formed by a mirror if m = -0.4?
nevsk [136]

Answer:

OPTION (C)

Explanation:

m(magnification) = -0.4 means a real, inverted and diminished image is formed in front of the mirror.

4 0
3 years ago
g A spherical container of inner diameter 0.9 meters contains nuclear waste that generates heat at the rate of 872 W/m3. Estimat
zhannawk [14.2K]

Answer: The total rate of heat transfer from the container to its surroundings ignoring radiation is 332.67 W.

Explanation:

Given: Inner diameter = 0.9 m

q = 872 W/m^{3}

Now, radii is calculated as follows.

r = \frac{diameter}{2}\\= \frac{0.9}{2}\\= 0.45 m

Hence, the rate of heat transfer is as follows.

Q = q \times V

where,

V = volume of sphere = \frac{4}{3} \pi r^{3}

Substitute the values into above formula as follows.

Q = q \times \frac{4}{3} \pi r^{3}\\= 872 W/m^{3} \times \frac{4}{3} \times 3.14 \times (0.45 m)^{3}\\= 332.67 W

Thus, we can conclude that the total rate of heat transfer from the container to its surroundings ignoring radiation is 332.67 W.

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3 years ago
Can you please match
Mama L [17]

Answer:

match what lol ?

3 0
3 years ago
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