Hi Pupil Here's Your answer ::
➡➡➡➡➡➡➡➡➡➡➡➡➡
No, on a circle in going from one point around circular path the displacement is zero but the distance covered is equal to the circumference of the circle.
i.e.
⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅
Hope this helps . . . . . . .
Convert 360 ns to Ms
1 answer:
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Hi Pupil Here's Your answer ::
➡➡➡➡➡➡➡➡➡➡➡➡➡
No, on a circle in going from one point around circular path the displacement is zero but the distance covered is equal to the circumference of the circle.
i.e.
⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅
Hope this helps . . . . . . .
Answer: 0.5 seconds or 2.625 seconds
Explanation:
At t = 0, The ball is 4 ft above the ground.
The height of the football varies with time in the following way:
s(t) = -16 t² + 50 t + 4
we need to find the time in which the height would of the football would be 25 ft:
⇒25 = -16 t² + 50 t + 4
we need to solve the quadratic equation:
⇒ 16 t² - 50 t + 21 = 0
⇒ t = 0.5 s or 2.625 s
Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.